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The hit ratio of a page is 0.35 in a paged memory. It requires 100 ns for accessing a page in secondary memory. It requires 10 ns for accessing a page in primary memory. What will be the average time (in ns) required to access a page? (Answer up to one decimal place
Correct answer is '68.5'. Can you explain this answer?
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The hit ratio of a page is 0.35 in a paged memory. It requires 100 ns ...
Given:
- Hit ratio of a page in paged memory = 0.35
- Time required for accessing a page in secondary memory = 100 ns
- Time required for accessing a page in primary memory = 10 ns
To find:
The average time required to access a page.
Solution:
The average time required to access a page can be calculated using the formula:
Average Access Time = Hit Ratio * Time for Hit + (1 - Hit Ratio) * Time for Miss
where,
- Hit Ratio is the probability that a page requested is already present in primary memory.
- Time for Hit is the time required to access a page when it is already present in primary memory (i.e., a hit).
- Time for Miss is the time required to access a page when it is not present in primary memory and needs to be fetched from secondary memory (i.e., a miss).
Calculating Time for Hit:
Since the page is already present in primary memory, the time required to access it is 10 ns.
Calculating Time for Miss:
When a page is not present in primary memory, it needs to be fetched from secondary memory. This process takes 100 ns.
Calculating the Average Access Time:
Average Access Time = 0.35 * 10 ns + (1 - 0.35) * 100 ns
= 3.5 ns + 0.65 * 100 ns
= 3.5 ns + 65 ns
= 68.5 ns
Therefore, the average time required to access a page is 68.5 ns.
- Hit ratio of a page in paged memory = 0.35
- Time required for accessing a page in secondary memory = 100 ns
- Time required for accessing a page in primary memory = 10 ns
To find:
The average time required to access a page.
Solution:
The average time required to access a page can be calculated using the formula:
Average Access Time = Hit Ratio * Time for Hit + (1 - Hit Ratio) * Time for Miss
where,
- Hit Ratio is the probability that a page requested is already present in primary memory.
- Time for Hit is the time required to access a page when it is already present in primary memory (i.e., a hit).
- Time for Miss is the time required to access a page when it is not present in primary memory and needs to be fetched from secondary memory (i.e., a miss).
Calculating Time for Hit:
Since the page is already present in primary memory, the time required to access it is 10 ns.
Calculating Time for Miss:
When a page is not present in primary memory, it needs to be fetched from secondary memory. This process takes 100 ns.
Calculating the Average Access Time:
Average Access Time = 0.35 * 10 ns + (1 - 0.35) * 100 ns
= 3.5 ns + 0.65 * 100 ns
= 3.5 ns + 65 ns
= 68.5 ns
Therefore, the average time required to access a page is 68.5 ns.
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Community Answer
The hit ratio of a page is 0.35 in a paged memory. It requires 100 ns ...
Hit ratio, h = 0.35
Time (secondary memory) = 100 ns
T (primary memory) = 10 ns
Average access time = h(Tm) + (1 - (h) × 100)
= 0.35 × 10 + (0.65 × 100)
= 3.5 + 65
= 68.5 ns
Time (secondary memory) = 100 ns
T (primary memory) = 10 ns
Average access time = h(Tm) + (1 - (h) × 100)
= 0.35 × 10 + (0.65 × 100)
= 3.5 + 65
= 68.5 ns
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The hit ratio of a page is 0.35 in a paged memory. It requires 100 ns for accessing a page in secondary memory. It requires 10 ns for accessing a page in primary memory. What will be the average time (in ns) required to access a page? (Answer up to one decimal placeCorrect answer is '68.5'. Can you explain this answer?
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