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Consider a disk I/O transfer, in which 1500 bytes are to be transferred. But the number of bytes on a track is 1000, and notation speed of disk is 1500 rps. The average time required to move the disk arm to the required track is 15 ms. What will be the total access time (in ms)? (Answer up to two decimal places)
    Correct answer is '16.33'. Can you explain this answer?
    Most Upvoted Answer
    Consider a disk I/O transfer, in which 1500 bytes are to be transferre...
     Ta = Ts + 1/2r + b/rN
    Here,
    Ta → transfer time
    Ts → average seek time = 15 ms
    r → rotation speed in rpms = 1500 rps
    b → number of bytes to be transferred = 1500 bytes
    N → number of bytes on a track = 1000 bytes
    = 16.33 ms
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    Consider a disk I/O transfer, in which 1500 bytes are to be transferred. But the number of bytes on a track is 1000, and notation speed of disk is 1500 rps. The average time required to move the disk arm to the required track is 15 ms. What will be the total access time (in ms)? (Answer up to two decimal places)Correct answer is '16.33'. Can you explain this answer?
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    Consider a disk I/O transfer, in which 1500 bytes are to be transferred. But the number of bytes on a track is 1000, and notation speed of disk is 1500 rps. The average time required to move the disk arm to the required track is 15 ms. What will be the total access time (in ms)? (Answer up to two decimal places)Correct answer is '16.33'. Can you explain this answer? for Computer Science Engineering (CSE) 2024 is part of Computer Science Engineering (CSE) preparation. The Question and answers have been prepared according to the Computer Science Engineering (CSE) exam syllabus. Information about Consider a disk I/O transfer, in which 1500 bytes are to be transferred. But the number of bytes on a track is 1000, and notation speed of disk is 1500 rps. The average time required to move the disk arm to the required track is 15 ms. What will be the total access time (in ms)? (Answer up to two decimal places)Correct answer is '16.33'. Can you explain this answer? covers all topics & solutions for Computer Science Engineering (CSE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Consider a disk I/O transfer, in which 1500 bytes are to be transferred. But the number of bytes on a track is 1000, and notation speed of disk is 1500 rps. The average time required to move the disk arm to the required track is 15 ms. What will be the total access time (in ms)? (Answer up to two decimal places)Correct answer is '16.33'. Can you explain this answer?.
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