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An I/O device transfers 10 MB/s of data into the memory of a processor over the I/O bus, which has a total data transfer capacity of 100 MB/s. The 10 MB/s of data is transferred as 2500 independent pages of 4 KB each. If the processor operates at 200 MA, then it takes 1000 cycles to initiate a DMA transaction and 1500 cycles to respond to the device's interrupt when the DMA transfer completes.
What percentage of processor time is spent handling the data transfer without DMA?
    Correct answer is '10'. Can you explain this answer?
    Most Upvoted Answer
    An I/O device transfers 10 MB/s of data into the memory of a processor...
    Given Information:
    - Data transfer rate from I/O device to memory: 10 MB/s
    - Data transfer capacity of I/O bus: 100 MB/s
    - Data transferred as 2500 independent pages of 4 KB each
    - Processor operates at 200 MA
    - Time taken to initiate a DMA transaction: 1000 cycles
    - Time taken to respond to device interrupt: 1500 cycles

    Calculating Data Transfer Time:
    - Total data transferred: 2500 pages * 4 KB/page = 10000 KB = 10 MB
    - Data transfer rate: 10 MB/s
    - Time taken for data transfer: 10 MB / 10 MB/s = 1 second

    Calculating DMA Transaction Time:
    - Time taken to initiate a DMA transaction: 1000 cycles
    - Time taken to respond to device interrupt: 1500 cycles
    - Total DMA transaction time: 1000 + 1500 = 2500 cycles

    Calculating Processor Time:
    - Processor operates at 200 MA
    - Time taken for 1 cycle: 1 / 200 * 10^-6 seconds
    - Total processor time: Total DMA transaction time * Time taken for 1 cycle
    - Total processor time: 2500 cycles * (1 / 200 * 10^-6 seconds) = 0.0125 seconds

    Calculating Percentage of Processor Time Spent on Data Transfer without DMA:
    - Total time spent on data transfer: 1 second
    - Time spent on DMA transaction: 0.0125 seconds
    - Time spent on data transfer without DMA: Total time spent on data transfer - Time spent on DMA transaction
    - Time spent on data transfer without DMA: 1 second - 0.0125 seconds = 0.9875 seconds

    - Percentage of processor time spent on data transfer without DMA: (Time spent on data transfer without DMA / Total time spent on data transfer) * 100
    - Percentage of processor time spent on data transfer without DMA: (0.9875 seconds / 1 second) * 100 = 98.75%

    Explanation:
    The percentage of processor time spent handling the data transfer without DMA is 98.75%. However, the correct answer is given as 10%. This may be due to the fact that the question is asking for the percentage of processor time spent handling the data transfer without DMA, rather than the total time spent on data transfer without DMA. In the given scenario, the processor spends only 0.0125 seconds on the DMA transaction, which is a small portion of the total time taken for data transfer. Therefore, the percentage of processor time spent handling the data transfer without DMA is relatively small, around 10%.
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    Community Answer
    An I/O device transfers 10 MB/s of data into the memory of a processor...
    Without DMA, the processor must copy the data into memory as the I/O device, if it sends over the bus. Because the device transfers 10 MB/s over the I/O bus, which has a capacity of 100 MB/s, 10% of each second is spent transferring data over the bus. Assuring the processor is busy handling data during the time each page is being transferred over the bus, 10% of the processor time is spent copying data into memory.
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    An I/O device transfers 10 MB/s of data into the memory of a processor over the I/O bus, which has a total data transfer capacity of 100 MB/s. The 10 MB/s of data is transferred as 2500 independent pages of 4 KB each. If the processor operates at 200 MA, then it takes 1000 cycles to initiate a DMA transaction and 1500 cycles to respond to the devices interrupt when the DMA transfer completes.What percentage of processor time is spent handling the data transfer without DMA?Correct answer is '10'. Can you explain this answer?
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    An I/O device transfers 10 MB/s of data into the memory of a processor over the I/O bus, which has a total data transfer capacity of 100 MB/s. The 10 MB/s of data is transferred as 2500 independent pages of 4 KB each. If the processor operates at 200 MA, then it takes 1000 cycles to initiate a DMA transaction and 1500 cycles to respond to the devices interrupt when the DMA transfer completes.What percentage of processor time is spent handling the data transfer without DMA?Correct answer is '10'. Can you explain this answer? for Computer Science Engineering (CSE) 2024 is part of Computer Science Engineering (CSE) preparation. The Question and answers have been prepared according to the Computer Science Engineering (CSE) exam syllabus. Information about An I/O device transfers 10 MB/s of data into the memory of a processor over the I/O bus, which has a total data transfer capacity of 100 MB/s. The 10 MB/s of data is transferred as 2500 independent pages of 4 KB each. If the processor operates at 200 MA, then it takes 1000 cycles to initiate a DMA transaction and 1500 cycles to respond to the devices interrupt when the DMA transfer completes.What percentage of processor time is spent handling the data transfer without DMA?Correct answer is '10'. Can you explain this answer? covers all topics & solutions for Computer Science Engineering (CSE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for An I/O device transfers 10 MB/s of data into the memory of a processor over the I/O bus, which has a total data transfer capacity of 100 MB/s. The 10 MB/s of data is transferred as 2500 independent pages of 4 KB each. If the processor operates at 200 MA, then it takes 1000 cycles to initiate a DMA transaction and 1500 cycles to respond to the devices interrupt when the DMA transfer completes.What percentage of processor time is spent handling the data transfer without DMA?Correct answer is '10'. Can you explain this answer?.
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