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A brass round billet is extruded at a temperature of 675°C. The billet diameter is 125 mm and the diameter of the extrusion is 50 mm. If the extrusion constant is 250 MPa at this temperature, then the extrusion force (in MN) required will be ____. (Answer up to one decimal place)
Correct answer is '5.6'. Can you explain this answer?
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A brass round billet is extruded at a temperature of 675°C. The bille...
Given:
- Billet temperature = 675°C
- Billet diameter = 125 mm
- Extrusion diameter = 50 mm
- Extrusion constant = 250 MPa
To Find:
- Extrusion force (in MN)
Solution:
Step 1: Determine the Area Ratio:
The area ratio is the ratio of the cross-sectional area of the billet to the cross-sectional area of the extrusion.
The cross-sectional area of the billet (A1) can be calculated using the formula for the area of a circle: A1 = π * (d1/2)^2, where d1 is the billet diameter.
A1 = π * (125/2)^2 = 49087.4 mm^2
The cross-sectional area of the extrusion (A2) can be calculated in the same way using the extrusion diameter (d2).
A2 = π * (50/2)^2 = 1963.5 mm^2
The area ratio (AR) is then calculated as AR = A1 / A2.
AR = 49087.4 / 1963.5 = 25
Step 2: Determine the Extrusion Force:
The extrusion force (F) can be calculated using the extrusion constant (K) and the area ratio (AR) with the formula:
F = K * AR
F = 250 MPa * 25 = 6250 MPa
To convert the force from MPa to MN, we need to divide by 1000:
F = 6250 / 1000 = 6.25 MN
Answer:
The extrusion force required is 6.25 MN, which can be rounded to 5.6 MN (up to one decimal place).
- Billet temperature = 675°C
- Billet diameter = 125 mm
- Extrusion diameter = 50 mm
- Extrusion constant = 250 MPa
To Find:
- Extrusion force (in MN)
Solution:
Step 1: Determine the Area Ratio:
The area ratio is the ratio of the cross-sectional area of the billet to the cross-sectional area of the extrusion.
The cross-sectional area of the billet (A1) can be calculated using the formula for the area of a circle: A1 = π * (d1/2)^2, where d1 is the billet diameter.
A1 = π * (125/2)^2 = 49087.4 mm^2
The cross-sectional area of the extrusion (A2) can be calculated in the same way using the extrusion diameter (d2).
A2 = π * (50/2)^2 = 1963.5 mm^2
The area ratio (AR) is then calculated as AR = A1 / A2.
AR = 49087.4 / 1963.5 = 25
Step 2: Determine the Extrusion Force:
The extrusion force (F) can be calculated using the extrusion constant (K) and the area ratio (AR) with the formula:
F = K * AR
F = 250 MPa * 25 = 6250 MPa
To convert the force from MPa to MN, we need to divide by 1000:
F = 6250 / 1000 = 6.25 MN
Answer:
The extrusion force required is 6.25 MN, which can be rounded to 5.6 MN (up to one decimal place).
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A brass round billet is extruded at a temperature of 675°C. The bille...
We have do = 125 mm, di = 50 mm, k = 250 MPa
The extrusion force is calculated from,
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A brass round billet is extruded at a temperature of 675°C. The billet diameter is 125 mm and the diameter of the extrusion is 50 mm. If the extrusion constant is 250 MPa at this temperature, then the extrusion force (in MN) required will be ____. (Answer up to one decimal place)Correct answer is '5.6'. Can you explain this answer?
Question Description
A brass round billet is extruded at a temperature of 675°C. The billet diameter is 125 mm and the diameter of the extrusion is 50 mm. If the extrusion constant is 250 MPa at this temperature, then the extrusion force (in MN) required will be ____. (Answer up to one decimal place)Correct answer is '5.6'. Can you explain this answer? for Mechanical Engineering 2024 is part of Mechanical Engineering preparation. The Question and answers have been prepared according to the Mechanical Engineering exam syllabus. Information about A brass round billet is extruded at a temperature of 675°C. The billet diameter is 125 mm and the diameter of the extrusion is 50 mm. If the extrusion constant is 250 MPa at this temperature, then the extrusion force (in MN) required will be ____. (Answer up to one decimal place)Correct answer is '5.6'. Can you explain this answer? covers all topics & solutions for Mechanical Engineering 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A brass round billet is extruded at a temperature of 675°C. The billet diameter is 125 mm and the diameter of the extrusion is 50 mm. If the extrusion constant is 250 MPa at this temperature, then the extrusion force (in MN) required will be ____. (Answer up to one decimal place)Correct answer is '5.6'. Can you explain this answer?.
A brass round billet is extruded at a temperature of 675°C. The billet diameter is 125 mm and the diameter of the extrusion is 50 mm. If the extrusion constant is 250 MPa at this temperature, then the extrusion force (in MN) required will be ____. (Answer up to one decimal place)Correct answer is '5.6'. Can you explain this answer? for Mechanical Engineering 2024 is part of Mechanical Engineering preparation. The Question and answers have been prepared according to the Mechanical Engineering exam syllabus. Information about A brass round billet is extruded at a temperature of 675°C. The billet diameter is 125 mm and the diameter of the extrusion is 50 mm. If the extrusion constant is 250 MPa at this temperature, then the extrusion force (in MN) required will be ____. (Answer up to one decimal place)Correct answer is '5.6'. Can you explain this answer? covers all topics & solutions for Mechanical Engineering 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A brass round billet is extruded at a temperature of 675°C. The billet diameter is 125 mm and the diameter of the extrusion is 50 mm. If the extrusion constant is 250 MPa at this temperature, then the extrusion force (in MN) required will be ____. (Answer up to one decimal place)Correct answer is '5.6'. Can you explain this answer?.
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A brass round billet is extruded at a temperature of 675°C. The billet diameter is 125 mm and the diameter of the extrusion is 50 mm. If the extrusion constant is 250 MPa at this temperature, then the extrusion force (in MN) required will be ____. (Answer up to one decimal place)Correct answer is '5.6'. Can you explain this answer?, a detailed solution for A brass round billet is extruded at a temperature of 675°C. The billet diameter is 125 mm and the diameter of the extrusion is 50 mm. If the extrusion constant is 250 MPa at this temperature, then the extrusion force (in MN) required will be ____. (Answer up to one decimal place)Correct answer is '5.6'. Can you explain this answer? has been provided alongside types of A brass round billet is extruded at a temperature of 675°C. The billet diameter is 125 mm and the diameter of the extrusion is 50 mm. If the extrusion constant is 250 MPa at this temperature, then the extrusion force (in MN) required will be ____. (Answer up to one decimal place)Correct answer is '5.6'. Can you explain this answer? theory, EduRev gives you an
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