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For a structural member, dead load = 20 kN and live load = 12 kN. What will be its design load as per the limit state of collapse philosophy?
- a)20 kN
- b)48 kN
- c)32 kN
- d)8 kN
Correct answer is option 'B'. Can you explain this answer?
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For a structural member, dead load = 20 kN and live load = 12 kN. What...
Limit State of Collapse Philosophy
The limit state of collapse philosophy is a design approach that ensures that the structure can resist all the applied loads without collapsing. In this approach, the design load is calculated based on the maximum expected loads on the structure.
Calculation of Design Load
Dead Load = 20 kN
Live Load = 12 kN
The design load is calculated as the sum of the dead load and live load. Therefore,
Design Load = Dead Load + Live Load
Design Load = 20 kN + 12 kN
Design Load = 32 kN
However, the limit state of collapse philosophy requires the design load to be multiplied by a factor of 1.5 to account for uncertainties in the loads and material properties.
Design Load (LSF) = 1.5 x Design Load
Design Load (LSF) = 1.5 x 32 kN
Design Load (LSF) = 48 kN
Therefore, the design load as per the limit state of collapse philosophy is 48 kN.
The limit state of collapse philosophy is a design approach that ensures that the structure can resist all the applied loads without collapsing. In this approach, the design load is calculated based on the maximum expected loads on the structure.
Calculation of Design Load
Dead Load = 20 kN
Live Load = 12 kN
The design load is calculated as the sum of the dead load and live load. Therefore,
Design Load = Dead Load + Live Load
Design Load = 20 kN + 12 kN
Design Load = 32 kN
However, the limit state of collapse philosophy requires the design load to be multiplied by a factor of 1.5 to account for uncertainties in the loads and material properties.
Design Load (LSF) = 1.5 x Design Load
Design Load (LSF) = 1.5 x 32 kN
Design Load (LSF) = 48 kN
Therefore, the design load as per the limit state of collapse philosophy is 48 kN.
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For a structural member, dead load = 20 kN and live load = 12 kN. What...
Values of the factor of safety (partial) for load combination:
Where, DL = Dead load, LL = Live load WL = Wind load EL = Earthquake load
Calculation:
Given: Dead load (DL) = 20 KN and Live load (LL) = 12 kN
Partial factor of safety = 1.5 (DL + LL) = 1.5 (20 + 12) = 48 kN
Additional Information
Values of the factor of safety (partial) for load combination:
Where, DL = Dead load, LL = Live load WL = Wind load EL = Earthquake load
Calculation:
Given: Dead load (DL) = 20 KN and Live load (LL) = 12 kN
Partial factor of safety = 1.5 (DL + LL) = 1.5 (20 + 12) = 48 kN
Additional Information
Values of the factor of safety (partial) for load combination:
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For a structural member, dead load = 20 kN and live load = 12 kN. What will be its design load as per the limit state of collapse philosophy?a)20 kNb)48 kNc)32 kNd)8 kNCorrect answer is option 'B'. Can you explain this answer?
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