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A thermally insulating cylinder has a thermally insulating and frictionless movable partition in the middle, as shown in the figure below. On each side of the partition, there is one mole of an ideal gas, with specific heat at constant volume, CV= 2R. Here, R is the gas constant. Initially, each side has a volume V0and temperature T0. The left side has an electric heater, which is turned on at very low power to transfer heat Q to the gas on the left side. As a result the partition moves slowly towards the right reducing the right side volume to V0/2. Consequently, the gas temperatures on the left and the right sides become TLand TR, respectively. Ignore the changes in the temperatures of the cylinder, heater and the partition.Q. The value of Q/RT0 isa)4(2√2 + 1)b)4(2√2 - 1)c)(5√2 + 1)d)(5√2 - 1)Correct answer is option 'B'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared
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the JEE exam syllabus. Information about A thermally insulating cylinder has a thermally insulating and frictionless movable partition in the middle, as shown in the figure below. On each side of the partition, there is one mole of an ideal gas, with specific heat at constant volume, CV= 2R. Here, R is the gas constant. Initially, each side has a volume V0and temperature T0. The left side has an electric heater, which is turned on at very low power to transfer heat Q to the gas on the left side. As a result the partition moves slowly towards the right reducing the right side volume to V0/2. Consequently, the gas temperatures on the left and the right sides become TLand TR, respectively. Ignore the changes in the temperatures of the cylinder, heater and the partition.Q. The value of Q/RT0 isa)4(2√2 + 1)b)4(2√2 - 1)c)(5√2 + 1)d)(5√2 - 1)Correct answer is option 'B'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam.
Find important definitions, questions, meanings, examples, exercises and tests below for A thermally insulating cylinder has a thermally insulating and frictionless movable partition in the middle, as shown in the figure below. On each side of the partition, there is one mole of an ideal gas, with specific heat at constant volume, CV= 2R. Here, R is the gas constant. Initially, each side has a volume V0and temperature T0. The left side has an electric heater, which is turned on at very low power to transfer heat Q to the gas on the left side. As a result the partition moves slowly towards the right reducing the right side volume to V0/2. Consequently, the gas temperatures on the left and the right sides become TLand TR, respectively. Ignore the changes in the temperatures of the cylinder, heater and the partition.Q. The value of Q/RT0 isa)4(2√2 + 1)b)4(2√2 - 1)c)(5√2 + 1)d)(5√2 - 1)Correct answer is option 'B'. Can you explain this answer?.
Solutions for A thermally insulating cylinder has a thermally insulating and frictionless movable partition in the middle, as shown in the figure below. On each side of the partition, there is one mole of an ideal gas, with specific heat at constant volume, CV= 2R. Here, R is the gas constant. Initially, each side has a volume V0and temperature T0. The left side has an electric heater, which is turned on at very low power to transfer heat Q to the gas on the left side. As a result the partition moves slowly towards the right reducing the right side volume to V0/2. Consequently, the gas temperatures on the left and the right sides become TLand TR, respectively. Ignore the changes in the temperatures of the cylinder, heater and the partition.Q. The value of Q/RT0 isa)4(2√2 + 1)b)4(2√2 - 1)c)(5√2 + 1)d)(5√2 - 1)Correct answer is option 'B'. Can you explain this answer? in English & in Hindi are available as part of our courses for JEE.
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Here you can find the meaning of A thermally insulating cylinder has a thermally insulating and frictionless movable partition in the middle, as shown in the figure below. On each side of the partition, there is one mole of an ideal gas, with specific heat at constant volume, CV= 2R. Here, R is the gas constant. Initially, each side has a volume V0and temperature T0. The left side has an electric heater, which is turned on at very low power to transfer heat Q to the gas on the left side. As a result the partition moves slowly towards the right reducing the right side volume to V0/2. Consequently, the gas temperatures on the left and the right sides become TLand TR, respectively. Ignore the changes in the temperatures of the cylinder, heater and the partition.Q. The value of Q/RT0 isa)4(2√2 + 1)b)4(2√2 - 1)c)(5√2 + 1)d)(5√2 - 1)Correct answer is option 'B'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of
A thermally insulating cylinder has a thermally insulating and frictionless movable partition in the middle, as shown in the figure below. On each side of the partition, there is one mole of an ideal gas, with specific heat at constant volume, CV= 2R. Here, R is the gas constant. Initially, each side has a volume V0and temperature T0. The left side has an electric heater, which is turned on at very low power to transfer heat Q to the gas on the left side. As a result the partition moves slowly towards the right reducing the right side volume to V0/2. Consequently, the gas temperatures on the left and the right sides become TLand TR, respectively. Ignore the changes in the temperatures of the cylinder, heater and the partition.Q. The value of Q/RT0 isa)4(2√2 + 1)b)4(2√2 - 1)c)(5√2 + 1)d)(5√2 - 1)Correct answer is option 'B'. Can you explain this answer?, a detailed solution for A thermally insulating cylinder has a thermally insulating and frictionless movable partition in the middle, as shown in the figure below. On each side of the partition, there is one mole of an ideal gas, with specific heat at constant volume, CV= 2R. Here, R is the gas constant. Initially, each side has a volume V0and temperature T0. The left side has an electric heater, which is turned on at very low power to transfer heat Q to the gas on the left side. As a result the partition moves slowly towards the right reducing the right side volume to V0/2. Consequently, the gas temperatures on the left and the right sides become TLand TR, respectively. Ignore the changes in the temperatures of the cylinder, heater and the partition.Q. The value of Q/RT0 isa)4(2√2 + 1)b)4(2√2 - 1)c)(5√2 + 1)d)(5√2 - 1)Correct answer is option 'B'. Can you explain this answer? has been provided alongside types of A thermally insulating cylinder has a thermally insulating and frictionless movable partition in the middle, as shown in the figure below. On each side of the partition, there is one mole of an ideal gas, with specific heat at constant volume, CV= 2R. Here, R is the gas constant. Initially, each side has a volume V0and temperature T0. The left side has an electric heater, which is turned on at very low power to transfer heat Q to the gas on the left side. As a result the partition moves slowly towards the right reducing the right side volume to V0/2. Consequently, the gas temperatures on the left and the right sides become TLand TR, respectively. Ignore the changes in the temperatures of the cylinder, heater and the partition.Q. The value of Q/RT0 isa)4(2√2 + 1)b)4(2√2 - 1)c)(5√2 + 1)d)(5√2 - 1)Correct answer is option 'B'. Can you explain this answer? theory, EduRev gives you an
ample number of questions to practice A thermally insulating cylinder has a thermally insulating and frictionless movable partition in the middle, as shown in the figure below. On each side of the partition, there is one mole of an ideal gas, with specific heat at constant volume, CV= 2R. Here, R is the gas constant. Initially, each side has a volume V0and temperature T0. The left side has an electric heater, which is turned on at very low power to transfer heat Q to the gas on the left side. As a result the partition moves slowly towards the right reducing the right side volume to V0/2. Consequently, the gas temperatures on the left and the right sides become TLand TR, respectively. Ignore the changes in the temperatures of the cylinder, heater and the partition.Q. The value of Q/RT0 isa)4(2√2 + 1)b)4(2√2 - 1)c)(5√2 + 1)d)(5√2 - 1)Correct answer is option 'B'. Can you explain this answer? tests, examples and also practice JEE tests.