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A JFET amplifier with a voltage-divider biasing circuit has the following parameters: VP = – 2V, IDSS = 4mA, RD = 910Ω, RS = 3KΩ, R1 = 12MΩ, R2 = 8.57MΩ and VDD = 24 V. Solve the value of drain current ID at the operating point. Verify whether the FET will operate in the pinch-off region.?
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A JFET amplifier with a voltage-divider biasing circuit has the follow...
Solution:

Operating Point Calculation:

To calculate the operating point, we need to find the values of VGS and ID. We can use the voltage-divider biasing circuit equation to find VGS.

VGS = VDD * R2 / (R1 + R2)

VGS = 24 * 8.57 / (12 + 8.57) = 12.83 V

Now, we can use the drain current equation to find ID.

ID = IDSS * (1 - VGS / VP)²

ID = 4 * (1 - 12.83 / -2)² = 1.53 mA

Verification of Operation in Pinch-Off Region:

To verify whether the FET will operate in the pinch-off region, we need to check if the drain-source voltage is greater than the pinch-off voltage (VP).

VD = VDD - ID * RD

VD = 24 - 1.53 * 910 = 22.39 V

Since VD is greater than VP, the FET will operate in the pinch-off region.

Conclusion:

Hence, the drain current ID at the operating point is 1.53 mA, and the FET will operate in the pinch-off region.
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A JFET amplifier with a voltage-divider biasing circuit has the following parameters: VP = – 2V, IDSS = 4mA, RD = 910Ω, RS = 3KΩ, R1 = 12MΩ, R2 = 8.57MΩ and VDD = 24 V. Solve the value of drain current ID at the operating point. Verify whether the FET will operate in the pinch-off region.?
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A JFET amplifier with a voltage-divider biasing circuit has the following parameters: VP = – 2V, IDSS = 4mA, RD = 910Ω, RS = 3KΩ, R1 = 12MΩ, R2 = 8.57MΩ and VDD = 24 V. Solve the value of drain current ID at the operating point. Verify whether the FET will operate in the pinch-off region.? for Electronics and Communication Engineering (ECE) 2024 is part of Electronics and Communication Engineering (ECE) preparation. The Question and answers have been prepared according to the Electronics and Communication Engineering (ECE) exam syllabus. Information about A JFET amplifier with a voltage-divider biasing circuit has the following parameters: VP = – 2V, IDSS = 4mA, RD = 910Ω, RS = 3KΩ, R1 = 12MΩ, R2 = 8.57MΩ and VDD = 24 V. Solve the value of drain current ID at the operating point. Verify whether the FET will operate in the pinch-off region.? covers all topics & solutions for Electronics and Communication Engineering (ECE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A JFET amplifier with a voltage-divider biasing circuit has the following parameters: VP = – 2V, IDSS = 4mA, RD = 910Ω, RS = 3KΩ, R1 = 12MΩ, R2 = 8.57MΩ and VDD = 24 V. Solve the value of drain current ID at the operating point. Verify whether the FET will operate in the pinch-off region.?.
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