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In a pure orthogonal turning by a zero rake angle single point carbide cutting tool the shear force has been computed to be 400 N. If the cutting velocity 100 m/min Vc = , depth of cut t = 2.0 mm , feedS0 = 0.1 mm/revolution and chip flow velocity Vf = 20 m/min , then the shear strength τs of the material will be _______ MPa.(round off to two decimal places).Correct answer is '391.89'. Can you explain this answer? for Mechanical Engineering 2024 is part of Mechanical Engineering preparation. The Question and answers have been prepared according to the Mechanical Engineering exam syllabus. Information about In a pure orthogonal turning by a zero rake angle single point carbide cutting tool the shear force has been computed to be 400 N. If the cutting velocity 100 m/min Vc = , depth of cut t = 2.0 mm , feedS0 = 0.1 mm/revolution and chip flow velocity Vf = 20 m/min , then the shear strength τs of the material will be _______ MPa.(round off to two decimal places).Correct answer is '391.89'. Can you explain this answer? covers all topics & solutions for Mechanical Engineering 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for In a pure orthogonal turning by a zero rake angle single point carbide cutting tool the shear force has been computed to be 400 N. If the cutting velocity 100 m/min Vc = , depth of cut t = 2.0 mm , feedS0 = 0.1 mm/revolution and chip flow velocity Vf = 20 m/min , then the shear strength τs of the material will be _______ MPa.(round off to two decimal places).Correct answer is '391.89'. Can you explain this answer?.

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Here you can find the meaning of In a pure orthogonal turning by a zero rake angle single point carbide cutting tool the shear force has been computed to be 400 N. If the cutting velocity 100 m/min Vc = , depth of cut t = 2.0 mm , feedS0 = 0.1 mm/revolution and chip flow velocity Vf = 20 m/min , then the shear strength τs of the material will be _______ MPa.(round off to two decimal places).Correct answer is '391.89'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of In a pure orthogonal turning by a zero rake angle single point carbide cutting tool the shear force has been computed to be 400 N. If the cutting velocity 100 m/min Vc = , depth of cut t = 2.0 mm , feedS0 = 0.1 mm/revolution and chip flow velocity Vf = 20 m/min , then the shear strength τs of the material will be _______ MPa.(round off to two decimal places).Correct answer is '391.89'. Can you explain this answer?, a detailed solution for In a pure orthogonal turning by a zero rake angle single point carbide cutting tool the shear force has been computed to be 400 N. If the cutting velocity 100 m/min Vc = , depth of cut t = 2.0 mm , feedS0 = 0.1 mm/revolution and chip flow velocity Vf = 20 m/min , then the shear strength τs of the material will be _______ MPa.(round off to two decimal places).Correct answer is '391.89'. Can you explain this answer? has been provided alongside types of In a pure orthogonal turning by a zero rake angle single point carbide cutting tool the shear force has been computed to be 400 N. If the cutting velocity 100 m/min Vc = , depth of cut t = 2.0 mm , feedS0 = 0.1 mm/revolution and chip flow velocity Vf = 20 m/min , then the shear strength τs of the material will be _______ MPa.(round off to two decimal places).Correct answer is '391.89'. Can you explain this answer? theory, EduRev gives you an ample number of questions to practice In a pure orthogonal turning by a zero rake angle single point carbide cutting tool the shear force has been computed to be 400 N. If the cutting velocity 100 m/min Vc = , depth of cut t = 2.0 mm , feedS0 = 0.1 mm/revolution and chip flow velocity Vf = 20 m/min , then the shear strength τs of the material will be _______ MPa.(round off to two decimal places).Correct answer is '391.89'. Can you explain this answer? tests, examples and also practice Mechanical Engineering tests.