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The refractive indices of the core and cladding of an optical fiber are 1.50 and 1.48 respectively. The critical propagation angle, which is defined as the maximum angle that the light beam makes with the axis of the optical fiber to achieve the total internal reflection (round off to two decimal places) is ______ degree.
    Correct answer is '9.32'. Can you explain this answer?
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    The refractive indices of the core and cladding of an optical fiber ar...
    The critical propagation angle is the maximum angle at which a light beam can enter an optical fiber and still undergo total internal reflection. In order to calculate this angle, we need to use Snell's law and the concept of total internal reflection.

    - Snell's Law:
    Snell's law relates the angles of incidence and refraction for a light ray passing through the interface between two media with different refractive indices. It states that the ratio of the sine of the angle of incidence to the sine of the angle of refraction is constant:

    n1 * sin(theta1) = n2 * sin(theta2)

    where n1 and n2 are the refractive indices of the two media, and theta1 and theta2 are the angles of incidence and refraction, respectively.

    - Total Internal Reflection:
    When a light ray travels from a medium with a higher refractive index (e.g., core) to a medium with a lower refractive index (e.g., cladding), there is a critical angle at which the light ray no longer refracts but undergoes total internal reflection. This occurs when the angle of refraction becomes 90 degrees.

    - Calculation:
    In this case, the refractive index of the core (n1) is 1.50, and the refractive index of the cladding (n2) is 1.48. We want to find the critical angle (theta1) at which total internal reflection occurs.

    Using Snell's law, we can set theta2 to 90 degrees and solve for theta1:

    n1 * sin(theta1) = n2 * sin(theta2)

    1.50 * sin(theta1) = 1.48 * sin(90)

    sin(theta1) = (1.48 * sin(90)) / 1.50

    sin(theta1) = 1.48 / 1.50

    theta1 = arcsin(1.48 / 1.50)

    theta1 ≈ 9.32 degrees

    Therefore, the critical propagation angle for achieving total internal reflection in this optical fiber is approximately 9.32 degrees.
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    The refractive indices of the core and cladding of an optical fiber ar...
    Given
    Refractive index of core n1 = 1.50
    Refractive index of cladding n2 = 1.48
    According to the definition of critical propagation angle given in statement of question, θ1, which is made with optical fiber axis and leads total internal reflection (TIR) in optical fiber cable, so we can calculate θ1 as,
    Here, θA Acceptance angle
    θC= Critical angle
    θ1= Critical propagation angle
    Where, n1 = refractive index of core = 1.5 2
    n2= refractive index of cladding = 1.48
    Hence, the value of critical propagation angle that leads total internal reflection in optical fiber is 9.360
    Question_Type: 4
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    The refractive indices of the core and cladding of an optical fiber are 1.50 and 1.48 respectively. The critical propagation angle, which is defined as the maximum angle that the light beam makes with the axis of the optical fiber to achieve the total internal reflection (round off to two decimal places) is ______ degree.Correct answer is '9.32'. Can you explain this answer?
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    The refractive indices of the core and cladding of an optical fiber are 1.50 and 1.48 respectively. The critical propagation angle, which is defined as the maximum angle that the light beam makes with the axis of the optical fiber to achieve the total internal reflection (round off to two decimal places) is ______ degree.Correct answer is '9.32'. Can you explain this answer? for Electronics and Communication Engineering (ECE) 2024 is part of Electronics and Communication Engineering (ECE) preparation. The Question and answers have been prepared according to the Electronics and Communication Engineering (ECE) exam syllabus. Information about The refractive indices of the core and cladding of an optical fiber are 1.50 and 1.48 respectively. The critical propagation angle, which is defined as the maximum angle that the light beam makes with the axis of the optical fiber to achieve the total internal reflection (round off to two decimal places) is ______ degree.Correct answer is '9.32'. Can you explain this answer? covers all topics & solutions for Electronics and Communication Engineering (ECE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The refractive indices of the core and cladding of an optical fiber are 1.50 and 1.48 respectively. The critical propagation angle, which is defined as the maximum angle that the light beam makes with the axis of the optical fiber to achieve the total internal reflection (round off to two decimal places) is ______ degree.Correct answer is '9.32'. Can you explain this answer?.
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