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An optical fiber is kept along direction. The refractive indices for the electric fields along directions in the fiber are nx = 1.5000 and ny = 1.5001, respectively (nx ≠ ny) due to the imperfection in the fiber cross-section). The free space wavelength of a light wave propagating in the fiber is 1.5 μm. If the light wave is circularly polarized at the input of the fiber, the minimum propagation distance after which it becomes linearly polarized, in centimeter, is ___________.
    Correct answer is '0.36 to 0.38'. Can you explain this answer?
    Verified Answer
    An optical fiber is kept along direction. The refractive indices for t...
    For circular polarization the phase difference between Ex & Ey is π/2
    ⇒ The phase difference for linear polarization should be π
    So the wave must travel a minimum distance such that the extra phase difference of π/2 must occur.

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    An optical fiber is kept along direction. The refractive indices for the electric fields alongdirections in the fiber are nx = 1.5000 and ny = 1.5001, respectively(nx ≠ ny) due to theimperfection in the fiber cross-section). The free space wavelength of a light wave propagating in the fiber is 1.5 μm. If the light wave is circularly polarized at the input of the fiber, the minimum propagation distance after which it becomes linearly polarized, in centimeter, is ___________.Correct answer is '0.36 to 0.38'. Can you explain this answer?
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    An optical fiber is kept along direction. The refractive indices for the electric fields alongdirections in the fiber are nx = 1.5000 and ny = 1.5001, respectively(nx ≠ ny) due to theimperfection in the fiber cross-section). The free space wavelength of a light wave propagating in the fiber is 1.5 μm. If the light wave is circularly polarized at the input of the fiber, the minimum propagation distance after which it becomes linearly polarized, in centimeter, is ___________.Correct answer is '0.36 to 0.38'. Can you explain this answer? for Electronics and Communication Engineering (ECE) 2024 is part of Electronics and Communication Engineering (ECE) preparation. The Question and answers have been prepared according to the Electronics and Communication Engineering (ECE) exam syllabus. Information about An optical fiber is kept along direction. The refractive indices for the electric fields alongdirections in the fiber are nx = 1.5000 and ny = 1.5001, respectively(nx ≠ ny) due to theimperfection in the fiber cross-section). The free space wavelength of a light wave propagating in the fiber is 1.5 μm. If the light wave is circularly polarized at the input of the fiber, the minimum propagation distance after which it becomes linearly polarized, in centimeter, is ___________.Correct answer is '0.36 to 0.38'. Can you explain this answer? covers all topics & solutions for Electronics and Communication Engineering (ECE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for An optical fiber is kept along direction. The refractive indices for the electric fields alongdirections in the fiber are nx = 1.5000 and ny = 1.5001, respectively(nx ≠ ny) due to theimperfection in the fiber cross-section). The free space wavelength of a light wave propagating in the fiber is 1.5 μm. If the light wave is circularly polarized at the input of the fiber, the minimum propagation distance after which it becomes linearly polarized, in centimeter, is ___________.Correct answer is '0.36 to 0.38'. Can you explain this answer?.
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