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Cerium (IV) has a noble gas configuration. Which of the following is correct statement about it?
- a)It will not prefer to undergo redox reactions.
- b)It will prefer to gain electron and act as an oxidizing agent
- c)It will prefer to give away an electron and behave as reducing agent
- d)It acts as both, oxidizing and reducing agent.
Correct answer is option 'B'. Can you explain this answer?
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Cerium (IV) has a noble gas configuration. Which of the following is c...
Explanation:
Cerium (IV) ion has a noble gas configuration (Ce4+). This means that the outermost shell of the ion has eight electrons, which is the same electron configuration as a noble gas.
Cerium (IV) has an incomplete d-orbital, which makes it a strong oxidizing agent. It is because it can gain electrons to complete the d-orbital and achieve a stable configuration. Therefore, Cerium (IV) prefers to gain electrons and act as an oxidizing agent.
When Cerium (IV) acts as an oxidizing agent, it accepts electrons from other atoms or ions and gets reduced to Cerium (III) ion. For example, when Ce4+ is added to a solution containing Fe2+, Ce4+ oxidizes Fe2+ to Fe3+, and itself gets reduced to Ce3+.
Cerium (IV) can also act as a reducing agent in some reactions. However, it is not its preferred behavior. When Cerium (IV) acts as a reducing agent, it donates electrons to other atoms or ions and gets oxidized itself.
In conclusion, Cerium (IV) prefers to gain electrons and act as an oxidizing agent. It can also act as a reducing agent, but it is not its preferred behavior.
Cerium (IV) ion has a noble gas configuration (Ce4+). This means that the outermost shell of the ion has eight electrons, which is the same electron configuration as a noble gas.
Cerium (IV) has an incomplete d-orbital, which makes it a strong oxidizing agent. It is because it can gain electrons to complete the d-orbital and achieve a stable configuration. Therefore, Cerium (IV) prefers to gain electrons and act as an oxidizing agent.
When Cerium (IV) acts as an oxidizing agent, it accepts electrons from other atoms or ions and gets reduced to Cerium (III) ion. For example, when Ce4+ is added to a solution containing Fe2+, Ce4+ oxidizes Fe2+ to Fe3+, and itself gets reduced to Ce3+.
Cerium (IV) can also act as a reducing agent in some reactions. However, it is not its preferred behavior. When Cerium (IV) acts as a reducing agent, it donates electrons to other atoms or ions and gets oxidized itself.
In conclusion, Cerium (IV) prefers to gain electrons and act as an oxidizing agent. It can also act as a reducing agent, but it is not its preferred behavior.
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Cerium (IV) has a noble gas configuration. Which of the following is c...
Cerium exists in two different oxidation states: +3 and +4.
It shows Ce+4 acts as a strong oxidizing agent and accepts an electron.
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Cerium (IV) has a noble gas configuration. Which of the following is correct statement about it?a)It will not prefer to undergo redox reactions.b)It will prefer to gain electron and act as an oxidizing agentc)It will prefer to give away an electron and behave as reducing agentd)It acts as both, oxidizing and reducing agent.Correct answer is option 'B'. Can you explain this answer?
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Cerium (IV) has a noble gas configuration. Which of the following is correct statement about it?a)It will not prefer to undergo redox reactions.b)It will prefer to gain electron and act as an oxidizing agentc)It will prefer to give away an electron and behave as reducing agentd)It acts as both, oxidizing and reducing agent.Correct answer is option 'B'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about Cerium (IV) has a noble gas configuration. Which of the following is correct statement about it?a)It will not prefer to undergo redox reactions.b)It will prefer to gain electron and act as an oxidizing agentc)It will prefer to give away an electron and behave as reducing agentd)It acts as both, oxidizing and reducing agent.Correct answer is option 'B'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Cerium (IV) has a noble gas configuration. Which of the following is correct statement about it?a)It will not prefer to undergo redox reactions.b)It will prefer to gain electron and act as an oxidizing agentc)It will prefer to give away an electron and behave as reducing agentd)It acts as both, oxidizing and reducing agent.Correct answer is option 'B'. Can you explain this answer?.
Cerium (IV) has a noble gas configuration. Which of the following is correct statement about it?a)It will not prefer to undergo redox reactions.b)It will prefer to gain electron and act as an oxidizing agentc)It will prefer to give away an electron and behave as reducing agentd)It acts as both, oxidizing and reducing agent.Correct answer is option 'B'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about Cerium (IV) has a noble gas configuration. Which of the following is correct statement about it?a)It will not prefer to undergo redox reactions.b)It will prefer to gain electron and act as an oxidizing agentc)It will prefer to give away an electron and behave as reducing agentd)It acts as both, oxidizing and reducing agent.Correct answer is option 'B'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Cerium (IV) has a noble gas configuration. Which of the following is correct statement about it?a)It will not prefer to undergo redox reactions.b)It will prefer to gain electron and act as an oxidizing agentc)It will prefer to give away an electron and behave as reducing agentd)It acts as both, oxidizing and reducing agent.Correct answer is option 'B'. Can you explain this answer?.
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