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1 L aqueous solution of H2SO4 contains 0.02 m mol H2SO4. 50% of this solution is diluted with deionized water to give 1 L solution (A). In solution (A), 0.01 m mol of H2SO4 are added. Total m mols of H2SO4 in the final solution is ___________ × 103 m mols.
    Correct answer is '0'. Can you explain this answer?
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    1 L aqueous solution of H2SO4contains 0.02 m mol H2SO4. 50% of this so...
    First, we need to find out how many m mols of H2SO4 are present in the original 1 L solution:

    0.02 m mol H2SO4/L x 1 L = 0.02 m mol H2SO4

    When this solution is diluted with deionized water, the amount of H2SO4 remains the same, but the concentration is halved:

    0.02 m mol H2SO4/L x 0.5 = 0.01 m mol H2SO4/L

    So solution (A) contains 0.01 m mol H2SO4/L. When we add 0.01 m mol of H2SO4 to this solution, the total amount of H2SO4 becomes:

    0.01 m mol H2SO4/L + 0.01 m mol H2SO4/L = 0.02 m mol H2SO4/L

    Therefore, the total m mols of H2SO4 in the final solution is 0.02 m mol/L.
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    1 L aqueous solution of H2SO4contains 0.02 m mol H2SO4. 50% of this so...
    0.02 m mol of h2s04

    50 %of 0.02=0.01

    add, 0.01 in 2nd lii=0.02m mols

    0.02* 10^3*10^-3=0.00002*10^3=0answer
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    1 L aqueous solution of H2SO4contains 0.02 m mol H2SO4. 50% of this solution is diluted with deionized water to give 1 L solution (A). In solution (A), 0.01 m mol of H2SO4are added. Total m mols of H2SO4in the final solution is ___________ × 103m mols.Correct answer is '0'. Can you explain this answer?
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    1 L aqueous solution of H2SO4contains 0.02 m mol H2SO4. 50% of this solution is diluted with deionized water to give 1 L solution (A). In solution (A), 0.01 m mol of H2SO4are added. Total m mols of H2SO4in the final solution is ___________ × 103m mols.Correct answer is '0'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about 1 L aqueous solution of H2SO4contains 0.02 m mol H2SO4. 50% of this solution is diluted with deionized water to give 1 L solution (A). In solution (A), 0.01 m mol of H2SO4are added. Total m mols of H2SO4in the final solution is ___________ × 103m mols.Correct answer is '0'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for 1 L aqueous solution of H2SO4contains 0.02 m mol H2SO4. 50% of this solution is diluted with deionized water to give 1 L solution (A). In solution (A), 0.01 m mol of H2SO4are added. Total m mols of H2SO4in the final solution is ___________ × 103m mols.Correct answer is '0'. Can you explain this answer?.
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