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Two identical cells, each of emf 1.5 V are connected in parallel across a parallel combination of two resistors each of resistance 20Ω. A voltmeter connected in the circuit measures 1.2 V. The internal resistance of each cell is
- a)2.5Ω
- b)4Ω
- c)5Ω
- d)10Ω
Correct answer is option 'C'. Can you explain this answer?
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Two identical cells, each of emf 1.5 V are connected in parallel acros...
⇒ r = 5Ω
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Two identical cells, each of emf 1.5 V are connected in parallel acros...
To solve this problem, we can use Ohm's Law and the rules for combining resistors in parallel.
First, let's calculate the equivalent resistance of the two resistors in parallel. The formula for calculating the equivalent resistance of resistors in parallel is:
1/Req = 1/R1 + 1/R2
where Req is the equivalent resistance, R1 and R2 are the resistances of the individual resistors.
Substituting the given values into the formula, we get:
1/Req = 1/20 + 1/20
1/Req = 2/20
1/Req = 1/10
Taking the reciprocal of both sides, we get:
Req = 10Ω
Now, let's calculate the total current flowing through the parallel combination of resistors. Since the two identical cells are connected in parallel, their emf remains the same and we can consider them as a single cell with an emf of 1.5 V.
The formula for calculating the total current in a parallel circuit is:
Itotal = I1 + I2
where Itotal is the total current, I1 and I2 are the currents flowing through the individual resistors.
Since the two resistors are identical, the current flowing through each resistor is the same. Therefore, we can write:
Itotal = I1 + I1
Itotal = 2I1
The current through each resistor can be calculated using Ohm's Law:
I = V/R
where I is the current, V is the voltage, and R is the resistance.
Substituting the given values, we get:
I1 = 1.5 V / 20 Ω
I1 = 0.075 A
Now, substituting the value of I1 into the equation for Itotal, we get:
Itotal = 2 * 0.075 A
Itotal = 0.15 A
Therefore, the total current flowing through the parallel combination of resistors is 0.15 A.
First, let's calculate the equivalent resistance of the two resistors in parallel. The formula for calculating the equivalent resistance of resistors in parallel is:
1/Req = 1/R1 + 1/R2
where Req is the equivalent resistance, R1 and R2 are the resistances of the individual resistors.
Substituting the given values into the formula, we get:
1/Req = 1/20 + 1/20
1/Req = 2/20
1/Req = 1/10
Taking the reciprocal of both sides, we get:
Req = 10Ω
Now, let's calculate the total current flowing through the parallel combination of resistors. Since the two identical cells are connected in parallel, their emf remains the same and we can consider them as a single cell with an emf of 1.5 V.
The formula for calculating the total current in a parallel circuit is:
Itotal = I1 + I2
where Itotal is the total current, I1 and I2 are the currents flowing through the individual resistors.
Since the two resistors are identical, the current flowing through each resistor is the same. Therefore, we can write:
Itotal = I1 + I1
Itotal = 2I1
The current through each resistor can be calculated using Ohm's Law:
I = V/R
where I is the current, V is the voltage, and R is the resistance.
Substituting the given values, we get:
I1 = 1.5 V / 20 Ω
I1 = 0.075 A
Now, substituting the value of I1 into the equation for Itotal, we get:
Itotal = 2 * 0.075 A
Itotal = 0.15 A
Therefore, the total current flowing through the parallel combination of resistors is 0.15 A.
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Two identical cells, each of emf 1.5 V are connected in parallel across a parallel combination of two resistors each of resistance 20Ω. A voltmeter connected in the circuit measures 1.2 V. The internal resistance of each cell isa)2.5Ωb)4Ωc)5Ωd)10ΩCorrect answer is option 'C'. Can you explain this answer?
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Two identical cells, each of emf 1.5 V are connected in parallel across a parallel combination of two resistors each of resistance 20Ω. A voltmeter connected in the circuit measures 1.2 V. The internal resistance of each cell isa)2.5Ωb)4Ωc)5Ωd)10ΩCorrect answer is option 'C'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about Two identical cells, each of emf 1.5 V are connected in parallel across a parallel combination of two resistors each of resistance 20Ω. A voltmeter connected in the circuit measures 1.2 V. The internal resistance of each cell isa)2.5Ωb)4Ωc)5Ωd)10ΩCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Two identical cells, each of emf 1.5 V are connected in parallel across a parallel combination of two resistors each of resistance 20Ω. A voltmeter connected in the circuit measures 1.2 V. The internal resistance of each cell isa)2.5Ωb)4Ωc)5Ωd)10ΩCorrect answer is option 'C'. Can you explain this answer?.
Two identical cells, each of emf 1.5 V are connected in parallel across a parallel combination of two resistors each of resistance 20Ω. A voltmeter connected in the circuit measures 1.2 V. The internal resistance of each cell isa)2.5Ωb)4Ωc)5Ωd)10ΩCorrect answer is option 'C'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about Two identical cells, each of emf 1.5 V are connected in parallel across a parallel combination of two resistors each of resistance 20Ω. A voltmeter connected in the circuit measures 1.2 V. The internal resistance of each cell isa)2.5Ωb)4Ωc)5Ωd)10ΩCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Two identical cells, each of emf 1.5 V are connected in parallel across a parallel combination of two resistors each of resistance 20Ω. A voltmeter connected in the circuit measures 1.2 V. The internal resistance of each cell isa)2.5Ωb)4Ωc)5Ωd)10ΩCorrect answer is option 'C'. Can you explain this answer?.
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Two identical cells, each of emf 1.5 V are connected in parallel across a parallel combination of two resistors each of resistance 20Ω. A voltmeter connected in the circuit measures 1.2 V. The internal resistance of each cell isa)2.5Ωb)4Ωc)5Ωd)10ΩCorrect answer is option 'C'. Can you explain this answer?, a detailed solution for Two identical cells, each of emf 1.5 V are connected in parallel across a parallel combination of two resistors each of resistance 20Ω. A voltmeter connected in the circuit measures 1.2 V. The internal resistance of each cell isa)2.5Ωb)4Ωc)5Ωd)10ΩCorrect answer is option 'C'. Can you explain this answer? has been provided alongside types of Two identical cells, each of emf 1.5 V are connected in parallel across a parallel combination of two resistors each of resistance 20Ω. A voltmeter connected in the circuit measures 1.2 V. The internal resistance of each cell isa)2.5Ωb)4Ωc)5Ωd)10ΩCorrect answer is option 'C'. Can you explain this answer? theory, EduRev gives you an
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