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Nucleus A is having mass number 220 and its binding energy per nucleon is 5.6 MeV. It splits in two fragments 'B' and 'C' of mass numbers 105 and 115. The binding energy of nucleons in 'B' and 'C' is 6.4 MeV per nucleon. The energy Q released per fission will be:
- a)0.8 MeV
- b)275 MeV
- c)220 MeV
- d)176 MeV
Correct answer is option 'D'. Can you explain this answer?
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Most Upvoted Answer
Nucleus A is having mass number 220 and its binding energy per nucleon...
Given data:
Mass number of nucleus A = 220
Binding energy per nucleon of nucleus A = 5.6 MeV
Mass numbers of fragments B and C = 105 and 115
Binding energy per nucleon of fragments B and C = 6.4 MeV
We are required to find the energy Q released per fission.
To solve this problem, we will use the concept of conservation of mass and conservation of energy.
1. Conservation of Mass:
The total mass of the reactants (nucleus A) must be equal to the total mass of the products (fragments B and C). Mathematically,
Mass of nucleus A = Mass of fragment B + Mass of fragment C
220 = 105 + 115
2. Conservation of Energy:
The total binding energy of the reactants (nucleus A) must be equal to the total binding energy of the products (fragments B and C), plus the energy released (Q). Mathematically,
Binding energy of nucleus A = Binding energy of fragment B + Binding energy of fragment C + Energy released (Q)
Let's calculate the binding energy of nucleus A:
Binding energy of nucleus A = Binding energy per nucleon x Mass number of nucleus A
= 5.6 MeV x 220
= 1232 MeV
Similarly, let's calculate the binding energy of fragments B and C:
Binding energy of fragment B = Binding energy per nucleon x Mass number of fragment B
= 6.4 MeV x 105
= 672 MeV
Binding energy of fragment C = Binding energy per nucleon x Mass number of fragment C
= 6.4 MeV x 115
= 736 MeV
Now, let's substitute these values into the conservation of energy equation:
1232 MeV = 672 MeV + 736 MeV + Energy released (Q)
Energy released (Q) = 1232 MeV - 672 MeV - 736 MeV
= -176 MeV
The negative sign indicates that energy is released during the fission process.
Therefore, the energy Q released per fission is 176 MeV (option D).
Mass number of nucleus A = 220
Binding energy per nucleon of nucleus A = 5.6 MeV
Mass numbers of fragments B and C = 105 and 115
Binding energy per nucleon of fragments B and C = 6.4 MeV
We are required to find the energy Q released per fission.
To solve this problem, we will use the concept of conservation of mass and conservation of energy.
1. Conservation of Mass:
The total mass of the reactants (nucleus A) must be equal to the total mass of the products (fragments B and C). Mathematically,
Mass of nucleus A = Mass of fragment B + Mass of fragment C
220 = 105 + 115
2. Conservation of Energy:
The total binding energy of the reactants (nucleus A) must be equal to the total binding energy of the products (fragments B and C), plus the energy released (Q). Mathematically,
Binding energy of nucleus A = Binding energy of fragment B + Binding energy of fragment C + Energy released (Q)
Let's calculate the binding energy of nucleus A:
Binding energy of nucleus A = Binding energy per nucleon x Mass number of nucleus A
= 5.6 MeV x 220
= 1232 MeV
Similarly, let's calculate the binding energy of fragments B and C:
Binding energy of fragment B = Binding energy per nucleon x Mass number of fragment B
= 6.4 MeV x 105
= 672 MeV
Binding energy of fragment C = Binding energy per nucleon x Mass number of fragment C
= 6.4 MeV x 115
= 736 MeV
Now, let's substitute these values into the conservation of energy equation:
1232 MeV = 672 MeV + 736 MeV + Energy released (Q)
Energy released (Q) = 1232 MeV - 672 MeV - 736 MeV
= -176 MeV
The negative sign indicates that energy is released during the fission process.
Therefore, the energy Q released per fission is 176 MeV (option D).
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Community Answer
Nucleus A is having mass number 220 and its binding energy per nucleon...
220A → 105B + 115C
⇒ Q = [105 × 6.4 + 115 × 6.4] - [220 × 5.6] MeV
⇒Q = 176 MeV
⇒ Q = [105 × 6.4 + 115 × 6.4] - [220 × 5.6] MeV
⇒Q = 176 MeV
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Nucleus A is having mass number 220 and its binding energy per nucleon is 5.6 MeV. It splits in two fragments B and C of mass numbers 105 and 115. The binding energy of nucleons in B and C is 6.4 MeV per nucleon. The energy Q released per fission will be:a)0.8 MeVb)275 MeVc)220 MeVd)176 MeVCorrect answer is option 'D'. Can you explain this answer?
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Nucleus A is having mass number 220 and its binding energy per nucleon is 5.6 MeV. It splits in two fragments B and C of mass numbers 105 and 115. The binding energy of nucleons in B and C is 6.4 MeV per nucleon. The energy Q released per fission will be:a)0.8 MeVb)275 MeVc)220 MeVd)176 MeVCorrect answer is option 'D'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about Nucleus A is having mass number 220 and its binding energy per nucleon is 5.6 MeV. It splits in two fragments B and C of mass numbers 105 and 115. The binding energy of nucleons in B and C is 6.4 MeV per nucleon. The energy Q released per fission will be:a)0.8 MeVb)275 MeVc)220 MeVd)176 MeVCorrect answer is option 'D'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Nucleus A is having mass number 220 and its binding energy per nucleon is 5.6 MeV. It splits in two fragments B and C of mass numbers 105 and 115. The binding energy of nucleons in B and C is 6.4 MeV per nucleon. The energy Q released per fission will be:a)0.8 MeVb)275 MeVc)220 MeVd)176 MeVCorrect answer is option 'D'. Can you explain this answer?.
Nucleus A is having mass number 220 and its binding energy per nucleon is 5.6 MeV. It splits in two fragments B and C of mass numbers 105 and 115. The binding energy of nucleons in B and C is 6.4 MeV per nucleon. The energy Q released per fission will be:a)0.8 MeVb)275 MeVc)220 MeVd)176 MeVCorrect answer is option 'D'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about Nucleus A is having mass number 220 and its binding energy per nucleon is 5.6 MeV. It splits in two fragments B and C of mass numbers 105 and 115. The binding energy of nucleons in B and C is 6.4 MeV per nucleon. The energy Q released per fission will be:a)0.8 MeVb)275 MeVc)220 MeVd)176 MeVCorrect answer is option 'D'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Nucleus A is having mass number 220 and its binding energy per nucleon is 5.6 MeV. It splits in two fragments B and C of mass numbers 105 and 115. The binding energy of nucleons in B and C is 6.4 MeV per nucleon. The energy Q released per fission will be:a)0.8 MeVb)275 MeVc)220 MeVd)176 MeVCorrect answer is option 'D'. Can you explain this answer?.
Solutions for Nucleus A is having mass number 220 and its binding energy per nucleon is 5.6 MeV. It splits in two fragments B and C of mass numbers 105 and 115. The binding energy of nucleons in B and C is 6.4 MeV per nucleon. The energy Q released per fission will be:a)0.8 MeVb)275 MeVc)220 MeVd)176 MeVCorrect answer is option 'D'. Can you explain this answer? in English & in Hindi are available as part of our courses for JEE.
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Nucleus A is having mass number 220 and its binding energy per nucleon is 5.6 MeV. It splits in two fragments B and C of mass numbers 105 and 115. The binding energy of nucleons in B and C is 6.4 MeV per nucleon. The energy Q released per fission will be:a)0.8 MeVb)275 MeVc)220 MeVd)176 MeVCorrect answer is option 'D'. Can you explain this answer?, a detailed solution for Nucleus A is having mass number 220 and its binding energy per nucleon is 5.6 MeV. It splits in two fragments B and C of mass numbers 105 and 115. The binding energy of nucleons in B and C is 6.4 MeV per nucleon. The energy Q released per fission will be:a)0.8 MeVb)275 MeVc)220 MeVd)176 MeVCorrect answer is option 'D'. Can you explain this answer? has been provided alongside types of Nucleus A is having mass number 220 and its binding energy per nucleon is 5.6 MeV. It splits in two fragments B and C of mass numbers 105 and 115. The binding energy of nucleons in B and C is 6.4 MeV per nucleon. The energy Q released per fission will be:a)0.8 MeVb)275 MeVc)220 MeVd)176 MeVCorrect answer is option 'D'. Can you explain this answer? theory, EduRev gives you an
ample number of questions to practice Nucleus A is having mass number 220 and its binding energy per nucleon is 5.6 MeV. It splits in two fragments B and C of mass numbers 105 and 115. The binding energy of nucleons in B and C is 6.4 MeV per nucleon. The energy Q released per fission will be:a)0.8 MeVb)275 MeVc)220 MeVd)176 MeVCorrect answer is option 'D'. Can you explain this answer? tests, examples and also practice JEE tests.
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