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In the given right-angled triangle ABC, AB = 12 cm and AC = 15 cm. A square is inscribed in the triangle. One of the vertices of the square coincides with a vertex of the triangle. What is the maximum possible area (in cm2) of the square?
  • a)
    1296/49
  • b)
    25
  • c)
    1225/36
  • d)
    1225/64
Correct answer is option 'A'. Can you explain this answer?
Most Upvoted Answer
In the given right-angled triangle ABC, AB = 12 cm and AC = 15 cm. A ...
AB = 12 cm, AC = 15 cm
Triangle ADE and ABC are similar (By AA)
Let side of the square or DB or BF = x cm.
So, AD = (12 - x) cm, FC = (9 - x)
After putting the values above, we get side of the square = 36/7 cm
Hence, area of the square = (36/7)2
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Community Answer
In the given right-angled triangle ABC, AB = 12 cm and AC = 15 cm. A ...
AB = 12 cm, AC = 15 cm
Triangle ADE and ABC are similar (By AA)
Let side of the square or DB or BF = x cm.
So, AD = (12 - x) cm, FC = (9 - x)
After putting the values above, we get side of the square = 36/7 cm
Hence, area of the square = (36/7)2
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In the given right-angled triangle ABC, AB = 12 cm and AC = 15 cm. A square is inscribed in the triangle. One of the vertices of the square coincides with a vertex of the triangle. What is the maximum possible area (in cm2) of the square?a)1296/49b)25c)1225/36d)1225/64Correct answer is option 'A'. Can you explain this answer?
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