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The rate constants for decomposition of acetaldehyde have been measured over the temperature range 700-1000 K. The data has been analysed by plotting ln k vs 103/T graph. The value of activation energy for the reaction is ______ kJ mol-1. (Nearest integer)
(Given: R = 8.31 J K-1 mol-1)
    Correct answer is '154'. Can you explain this answer?
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    The rate constants for decomposition of acetaldehyde have been measure...


    ∴ Slope of the graph = 
    ∴ Ea = 18.5 × 8.31 × 1000 ≌ 154 kJ mol-1
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    The rate constants for decomposition of acetaldehyde have been measure...


    ∴ Slope of the graph = 
    ∴ Ea = 18.5 × 8.31 × 1000 ≌ 154 kJ mol-1
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    The rate constants for decomposition of acetaldehyde have been measured over the temperature range 700-1000 K. The data has been analysed by plotting ln k vs 103/Tgraph. The value of activation energy for the reaction is ______ kJ mol-1. (Nearest integer)(Given: R = 8.31 J K-1mol-1)Correct answer is '154'. Can you explain this answer?
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    The rate constants for decomposition of acetaldehyde have been measured over the temperature range 700-1000 K. The data has been analysed by plotting ln k vs 103/Tgraph. The value of activation energy for the reaction is ______ kJ mol-1. (Nearest integer)(Given: R = 8.31 J K-1mol-1)Correct answer is '154'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about The rate constants for decomposition of acetaldehyde have been measured over the temperature range 700-1000 K. The data has been analysed by plotting ln k vs 103/Tgraph. The value of activation energy for the reaction is ______ kJ mol-1. (Nearest integer)(Given: R = 8.31 J K-1mol-1)Correct answer is '154'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The rate constants for decomposition of acetaldehyde have been measured over the temperature range 700-1000 K. The data has been analysed by plotting ln k vs 103/Tgraph. The value of activation energy for the reaction is ______ kJ mol-1. (Nearest integer)(Given: R = 8.31 J K-1mol-1)Correct answer is '154'. Can you explain this answer?.
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