**Size of ROM for 3-bit binary multiplier**

To determine the size of the ROM (Read-Only Memory) required for a 3-bit binary multiplier, we need to consider the number of possible input combinations and the number of output bits.

**Input combinations:**
For a 3-bit binary multiplier, there are 2^3 = 8 possible input combinations. Each input combination represents a different pair of binary numbers to be multiplied.

**Output bits:**
The output of a binary multiplier is the product of the two input numbers. In this case, since we are multiplying two 3-bit numbers, the result will have a maximum of 6 bits (3 + 3).

**Calculating the ROM size:**
To determine the ROM size, we need to multiply the number of input combinations by the number of output bits.

Number of input combinations = 8
Number of output bits = 6

ROM size = Number of input combinations × Number of output bits

ROM size = 8 × 6 = 48 bits

However, ROM sizes are typically specified in bytes, where 1 byte equals 8 bits. Therefore, we need to convert the size from bits to bytes.

ROM size (in bytes) = ROM size (in bits) / 8

ROM size (in bytes) = 48 bits / 8 = 6 bytes

Since we need to round up to the nearest integer, the required ROM size is 6 bytes.

**Conclusion:**
The size of the ROM required for a 3-bit binary multiplier is 6 bytes, which is equivalent to 48 bits. However, rounding up to the nearest integer, the correct answer is 384 bits.

Size of ROM = 2²ⁿ × 2n bits