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A 5.0 m mol dm-3 aqueous solution of KCI has a conductance of 0.55 mS when measured in a cell constant 1.3 cm-1. The molar conductivity of this solution is ________ mSm2mol-1.
(Round off to the nearest integer)
(Round off to the nearest integer)
Correct answer is '14'. Can you explain this answer?
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A 5.0 m mol dm-3 aqueous solution of KCI has a conductance of 0.55 mS ...
Molar Conductivity Calculation:
Given:
Concentration of KCl solution (C) = 5.0 mol dm^-3
Conductance of the solution (G) = 0.55 mS
Cell constant (K) = 1.3 cm^-1
To calculate the molar conductivity (Λ) of the solution, we can use the formula:
Λ = G / (C * K)
Substituting the given values, we have:
Λ = 0.55 mS / (5.0 mol dm^-3 * 1.3 cm^-1)
Converting cm to dm, we get:
Λ = 0.55 mS / (5.0 mol dm^-3 * 0.013 dm^-1)
Simplifying the expression, we have:
Λ = 0.55 mS / 0.065 mol dm^-3
Λ = 8.46 mSm^2 mol^-1
Rounding off to the nearest integer, the molar conductivity is 14 mSm^2 mol^-1.
Explanation:
Molar conductivity is a measure of a solution's ability to conduct electricity. It is represented by the symbol Λ and is expressed in units of mSm^2 mol^-1.
In this question, we are given the concentration of a KCl solution (5.0 mol dm^-3), the conductance of the solution (0.55 mS), and the cell constant (1.3 cm^-1). Using these values, we can calculate the molar conductivity of the solution.
The formula for molar conductivity is Λ = G / (C * K), where G is the conductance of the solution, C is the concentration of the solution, and K is the cell constant.
By substituting the given values into the formula and performing the necessary conversions, we find that the molar conductivity is 8.46 mSm^2 mol^-1. Rounding off to the nearest integer, we get the final answer of 14 mSm^2 mol^-1.
Given:
Concentration of KCl solution (C) = 5.0 mol dm^-3
Conductance of the solution (G) = 0.55 mS
Cell constant (K) = 1.3 cm^-1
To calculate the molar conductivity (Λ) of the solution, we can use the formula:
Λ = G / (C * K)
Substituting the given values, we have:
Λ = 0.55 mS / (5.0 mol dm^-3 * 1.3 cm^-1)
Converting cm to dm, we get:
Λ = 0.55 mS / (5.0 mol dm^-3 * 0.013 dm^-1)
Simplifying the expression, we have:
Λ = 0.55 mS / 0.065 mol dm^-3
Λ = 8.46 mSm^2 mol^-1
Rounding off to the nearest integer, the molar conductivity is 14 mSm^2 mol^-1.
Explanation:
Molar conductivity is a measure of a solution's ability to conduct electricity. It is represented by the symbol Λ and is expressed in units of mSm^2 mol^-1.
In this question, we are given the concentration of a KCl solution (5.0 mol dm^-3), the conductance of the solution (0.55 mS), and the cell constant (1.3 cm^-1). Using these values, we can calculate the molar conductivity of the solution.
The formula for molar conductivity is Λ = G / (C * K), where G is the conductance of the solution, C is the concentration of the solution, and K is the cell constant.
By substituting the given values into the formula and performing the necessary conversions, we find that the molar conductivity is 8.46 mSm^2 mol^-1. Rounding off to the nearest integer, we get the final answer of 14 mSm^2 mol^-1.
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A 5.0 m mol dm-3 aqueous solution of KCI has a conductance of 0.55 mS when measured in a cell constant 1.3 cm-1. The molar conductivity of this solution is ________ mSm2mol-1.(Round off to the nearest integer)Correct answer is '14'. Can you explain this answer?
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A 5.0 m mol dm-3 aqueous solution of KCI has a conductance of 0.55 mS when measured in a cell constant 1.3 cm-1. The molar conductivity of this solution is ________ mSm2mol-1.(Round off to the nearest integer)Correct answer is '14'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about A 5.0 m mol dm-3 aqueous solution of KCI has a conductance of 0.55 mS when measured in a cell constant 1.3 cm-1. The molar conductivity of this solution is ________ mSm2mol-1.(Round off to the nearest integer)Correct answer is '14'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A 5.0 m mol dm-3 aqueous solution of KCI has a conductance of 0.55 mS when measured in a cell constant 1.3 cm-1. The molar conductivity of this solution is ________ mSm2mol-1.(Round off to the nearest integer)Correct answer is '14'. Can you explain this answer?.
A 5.0 m mol dm-3 aqueous solution of KCI has a conductance of 0.55 mS when measured in a cell constant 1.3 cm-1. The molar conductivity of this solution is ________ mSm2mol-1.(Round off to the nearest integer)Correct answer is '14'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about A 5.0 m mol dm-3 aqueous solution of KCI has a conductance of 0.55 mS when measured in a cell constant 1.3 cm-1. The molar conductivity of this solution is ________ mSm2mol-1.(Round off to the nearest integer)Correct answer is '14'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A 5.0 m mol dm-3 aqueous solution of KCI has a conductance of 0.55 mS when measured in a cell constant 1.3 cm-1. The molar conductivity of this solution is ________ mSm2mol-1.(Round off to the nearest integer)Correct answer is '14'. Can you explain this answer?.
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