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A block of 200 g mass moves with a uniform speed in a horizontal circular groove, with vertical side walls of radius 20 cm. If the block takes 40 s to complete one round, the normal force by the side walls of the groove is:
- a)0.0314 N
- b)9.859 × 10-2 N
- c)6.28 × 10-3 N
- d)9.859 × 10-4 N
Correct answer is option 'D'. Can you explain this answer?
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Most Upvoted Answer
A block of 200 g mass moves with a uniform speed in a horizontal circu...
We can start by finding the centripetal acceleration of the block.
The centripetal acceleration is given by the formula a = v^2/r, where v is the velocity and r is the radius of the circular path.
Since the block moves with a uniform speed, the magnitude of its velocity is constant.
The velocity can be found by dividing the circumference of the circular path by the time taken to complete one round.
The circumference of the circular path is given by 2πr.
Substituting the given values, we have v = 2π(0.2 m) / 40 s = 0.314 m/s.
Now we can find the centripetal acceleration:
a = (0.314 m/s)^2 / 0.2 m = 0.4925 m/s^2.
The normal force by the side walls of the groove will be equal to the centripetal force acting on the block.
The centripetal force is given by the formula F = ma, where m is the mass and a is the centripetal acceleration.
Substituting the given values, we have F = (0.2 kg)(0.4925 m/s^2) = 0.0985 N.
Therefore, the normal force by the side walls of the groove is 0.0985 N, which is approximately equal to 0.0314 N.
Therefore, the correct answer is (a) 0.0314 N.
The centripetal acceleration is given by the formula a = v^2/r, where v is the velocity and r is the radius of the circular path.
Since the block moves with a uniform speed, the magnitude of its velocity is constant.
The velocity can be found by dividing the circumference of the circular path by the time taken to complete one round.
The circumference of the circular path is given by 2πr.
Substituting the given values, we have v = 2π(0.2 m) / 40 s = 0.314 m/s.
Now we can find the centripetal acceleration:
a = (0.314 m/s)^2 / 0.2 m = 0.4925 m/s^2.
The normal force by the side walls of the groove will be equal to the centripetal force acting on the block.
The centripetal force is given by the formula F = ma, where m is the mass and a is the centripetal acceleration.
Substituting the given values, we have F = (0.2 kg)(0.4925 m/s^2) = 0.0985 N.
Therefore, the normal force by the side walls of the groove is 0.0985 N, which is approximately equal to 0.0314 N.
Therefore, the correct answer is (a) 0.0314 N.
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Community Answer
A block of 200 g mass moves with a uniform speed in a horizontal circu...
N = mω2R
Given: m = 0.2 kg, T = 40 S, R = 0.2 m
Put these values in equation (1).
N = 9.859 × 10-4 N
Given: m = 0.2 kg, T = 40 S, R = 0.2 m
Put these values in equation (1).
N = 9.859 × 10-4 N
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A block of 200 g mass moves with a uniform speed in a horizontal circular groove, with vertical side walls of radius 20 cm. If the block takes 40 s to complete one round, the normal force by the side walls of the groove is:a)0.0314 Nb)9.859 × 10-2 Nc)6.28 × 10-3 Nd)9.859 × 10-4 NCorrect answer is option 'D'. Can you explain this answer?
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A block of 200 g mass moves with a uniform speed in a horizontal circular groove, with vertical side walls of radius 20 cm. If the block takes 40 s to complete one round, the normal force by the side walls of the groove is:a)0.0314 Nb)9.859 × 10-2 Nc)6.28 × 10-3 Nd)9.859 × 10-4 NCorrect answer is option 'D'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about A block of 200 g mass moves with a uniform speed in a horizontal circular groove, with vertical side walls of radius 20 cm. If the block takes 40 s to complete one round, the normal force by the side walls of the groove is:a)0.0314 Nb)9.859 × 10-2 Nc)6.28 × 10-3 Nd)9.859 × 10-4 NCorrect answer is option 'D'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A block of 200 g mass moves with a uniform speed in a horizontal circular groove, with vertical side walls of radius 20 cm. If the block takes 40 s to complete one round, the normal force by the side walls of the groove is:a)0.0314 Nb)9.859 × 10-2 Nc)6.28 × 10-3 Nd)9.859 × 10-4 NCorrect answer is option 'D'. Can you explain this answer?.
A block of 200 g mass moves with a uniform speed in a horizontal circular groove, with vertical side walls of radius 20 cm. If the block takes 40 s to complete one round, the normal force by the side walls of the groove is:a)0.0314 Nb)9.859 × 10-2 Nc)6.28 × 10-3 Nd)9.859 × 10-4 NCorrect answer is option 'D'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about A block of 200 g mass moves with a uniform speed in a horizontal circular groove, with vertical side walls of radius 20 cm. If the block takes 40 s to complete one round, the normal force by the side walls of the groove is:a)0.0314 Nb)9.859 × 10-2 Nc)6.28 × 10-3 Nd)9.859 × 10-4 NCorrect answer is option 'D'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A block of 200 g mass moves with a uniform speed in a horizontal circular groove, with vertical side walls of radius 20 cm. If the block takes 40 s to complete one round, the normal force by the side walls of the groove is:a)0.0314 Nb)9.859 × 10-2 Nc)6.28 × 10-3 Nd)9.859 × 10-4 NCorrect answer is option 'D'. Can you explain this answer?.
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A block of 200 g mass moves with a uniform speed in a horizontal circular groove, with vertical side walls of radius 20 cm. If the block takes 40 s to complete one round, the normal force by the side walls of the groove is:a)0.0314 Nb)9.859 × 10-2 Nc)6.28 × 10-3 Nd)9.859 × 10-4 NCorrect answer is option 'D'. Can you explain this answer?, a detailed solution for A block of 200 g mass moves with a uniform speed in a horizontal circular groove, with vertical side walls of radius 20 cm. If the block takes 40 s to complete one round, the normal force by the side walls of the groove is:a)0.0314 Nb)9.859 × 10-2 Nc)6.28 × 10-3 Nd)9.859 × 10-4 NCorrect answer is option 'D'. Can you explain this answer? has been provided alongside types of A block of 200 g mass moves with a uniform speed in a horizontal circular groove, with vertical side walls of radius 20 cm. If the block takes 40 s to complete one round, the normal force by the side walls of the groove is:a)0.0314 Nb)9.859 × 10-2 Nc)6.28 × 10-3 Nd)9.859 × 10-4 NCorrect answer is option 'D'. Can you explain this answer? theory, EduRev gives you an
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