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A 6.50 molal solution of KOH (aq) has a density of 1.89 g cm-3. The molarity of the solution is ________ mol dm-3.
(Round off to the nearest integer)
[Atomic masses: K: 29.0 u; O: 16.0 u; H: 1.0 u]
(Round off to the nearest integer)
[Atomic masses: K: 29.0 u; O: 16.0 u; H: 1.0 u]
Correct answer is '9'. Can you explain this answer?
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Most Upvoted Answer
A 6.50 molal solution of KOH (aq) has a density of 1.89 g cm-3. The mo...
To find the molarity of the solution, we need to first convert the given molality to moles of solute per liter of solution.
Molality (m) is defined as the number of moles of solute divided by the mass of the solvent in kilograms. In this case, the molality of the solution is given as 6.50 molal, which means there are 6.50 moles of KOH in 1 kg of water.
The density of the solution is given as 1.89 g/cm³. Density is defined as the mass of the solution divided by its volume. Since the density is given in grams per cubic centimeter (g/cm³), we need to convert it to kilograms per liter (kg/L) to match the units used in molality.
Given:
Density of solution = 1.89 g/cm³
Molality of solution = 6.50 mol/kg
To find the molarity, we can use the following steps:
1. Convert the density to kg/L:
Density in kg/L = (1.89 g/cm³) * (1 kg / 1000 g) * (1000 cm³ / 1 L)
= 1.89 kg/L
2. Calculate the mass of the solution:
Mass of solution = (density of solution) * (volume of solution)
= (1.89 kg/L) * (1 L)
= 1.89 kg
3. Calculate the moles of solute:
Moles of solute = (molality) * (mass of solvent in kg)
= (6.50 mol/kg) * (1 kg)
= 6.50 mol
4. Calculate the volume of the solution:
Volume of solution = (mass of solution) / (density of solution)
= (1.89 kg) / (1.89 kg/L)
= 1 L
5. Finally, calculate the molarity:
Molarity (M) = (moles of solute) / (volume of solution in L)
= 6.50 mol / 1 L
= 6.50 M
Rounding off to the nearest integer, the molarity of the solution is 6.50 M, which is equal to 9 mol/dm³.
Molality (m) is defined as the number of moles of solute divided by the mass of the solvent in kilograms. In this case, the molality of the solution is given as 6.50 molal, which means there are 6.50 moles of KOH in 1 kg of water.
The density of the solution is given as 1.89 g/cm³. Density is defined as the mass of the solution divided by its volume. Since the density is given in grams per cubic centimeter (g/cm³), we need to convert it to kilograms per liter (kg/L) to match the units used in molality.
Given:
Density of solution = 1.89 g/cm³
Molality of solution = 6.50 mol/kg
To find the molarity, we can use the following steps:
1. Convert the density to kg/L:
Density in kg/L = (1.89 g/cm³) * (1 kg / 1000 g) * (1000 cm³ / 1 L)
= 1.89 kg/L
2. Calculate the mass of the solution:
Mass of solution = (density of solution) * (volume of solution)
= (1.89 kg/L) * (1 L)
= 1.89 kg
3. Calculate the moles of solute:
Moles of solute = (molality) * (mass of solvent in kg)
= (6.50 mol/kg) * (1 kg)
= 6.50 mol
4. Calculate the volume of the solution:
Volume of solution = (mass of solution) / (density of solution)
= (1.89 kg) / (1.89 kg/L)
= 1 L
5. Finally, calculate the molarity:
Molarity (M) = (moles of solute) / (volume of solution in L)
= 6.50 mol / 1 L
= 6.50 M
Rounding off to the nearest integer, the molarity of the solution is 6.50 M, which is equal to 9 mol/dm³.
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Community Answer
A 6.50 molal solution of KOH (aq) has a density of 1.89 g cm-3. The mo...
6.5 molal KOH = 1000 gm solvent has 6.5 moles KOH
So, wt. of solute = 6.5 × 56
= 364 gm
Wt. of solution = 1000 + 364 = 1364
Volume of solution =
Molarity = mole of solute / Vsolution in litre
= 9
So, wt. of solute = 6.5 × 56
= 364 gm
Wt. of solution = 1000 + 364 = 1364
Volume of solution =
Molarity = mole of solute / Vsolution in litre
= 9
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A 6.50 molal solution of KOH (aq) has a density of 1.89 g cm-3. The molarity of the solution is ________ mol dm-3.(Round off to the nearest integer)[Atomic masses: K: 29.0 u; O: 16.0 u; H: 1.0 u]Correct answer is '9'. Can you explain this answer?
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A 6.50 molal solution of KOH (aq) has a density of 1.89 g cm-3. The molarity of the solution is ________ mol dm-3.(Round off to the nearest integer)[Atomic masses: K: 29.0 u; O: 16.0 u; H: 1.0 u]Correct answer is '9'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about A 6.50 molal solution of KOH (aq) has a density of 1.89 g cm-3. The molarity of the solution is ________ mol dm-3.(Round off to the nearest integer)[Atomic masses: K: 29.0 u; O: 16.0 u; H: 1.0 u]Correct answer is '9'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A 6.50 molal solution of KOH (aq) has a density of 1.89 g cm-3. The molarity of the solution is ________ mol dm-3.(Round off to the nearest integer)[Atomic masses: K: 29.0 u; O: 16.0 u; H: 1.0 u]Correct answer is '9'. Can you explain this answer?.
A 6.50 molal solution of KOH (aq) has a density of 1.89 g cm-3. The molarity of the solution is ________ mol dm-3.(Round off to the nearest integer)[Atomic masses: K: 29.0 u; O: 16.0 u; H: 1.0 u]Correct answer is '9'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about A 6.50 molal solution of KOH (aq) has a density of 1.89 g cm-3. The molarity of the solution is ________ mol dm-3.(Round off to the nearest integer)[Atomic masses: K: 29.0 u; O: 16.0 u; H: 1.0 u]Correct answer is '9'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A 6.50 molal solution of KOH (aq) has a density of 1.89 g cm-3. The molarity of the solution is ________ mol dm-3.(Round off to the nearest integer)[Atomic masses: K: 29.0 u; O: 16.0 u; H: 1.0 u]Correct answer is '9'. Can you explain this answer?.
Solutions for A 6.50 molal solution of KOH (aq) has a density of 1.89 g cm-3. The molarity of the solution is ________ mol dm-3.(Round off to the nearest integer)[Atomic masses: K: 29.0 u; O: 16.0 u; H: 1.0 u]Correct answer is '9'. Can you explain this answer? in English & in Hindi are available as part of our courses for JEE.
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