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If the concentration of glucose (C6H12O6) in blood is 0.72 g L-1, the molarity of glucose in blood is _______ × 10-3 M. (Nearest integer)
(Given: Atomic mass of C = 12, H = 1, O = 16 u)
(Given: Atomic mass of C = 12, H = 1, O = 16 u)
Correct answer is '4'. Can you explain this answer?
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If the concentration of glucose (C6H12O6) in blood is 0.72 g L-1, the ...
To find the molarity of glucose in blood, we need to convert the concentration from grams per liter (g/L) to moles per liter (mol/L or M).
First, we need to determine the molar mass of glucose (C6H12O6):
1 carbon atom (C) has a molar mass of 12.01 g/mol
6 hydrogen atoms (H) have a molar mass of 1.01 g/mol each, so a total of 6.06 g/mol
6 oxygen atoms (O) have a molar mass of 16.00 g/mol each, so a total of 96.00 g/mol
Adding these together, we get:
12.01 g/mol (C) + 6.06 g/mol (H) + 96.00 g/mol (O) = 114.07 g/mol
Now, we can convert the concentration from grams per liter (g/L) to moles per liter (mol/L):
0.72 g/L / 114.07 g/mol ≈ 0.00631 mol/L
Therefore, the molarity of glucose in blood is approximately 0.00631 M.
First, we need to determine the molar mass of glucose (C6H12O6):
1 carbon atom (C) has a molar mass of 12.01 g/mol
6 hydrogen atoms (H) have a molar mass of 1.01 g/mol each, so a total of 6.06 g/mol
6 oxygen atoms (O) have a molar mass of 16.00 g/mol each, so a total of 96.00 g/mol
Adding these together, we get:
12.01 g/mol (C) + 6.06 g/mol (H) + 96.00 g/mol (O) = 114.07 g/mol
Now, we can convert the concentration from grams per liter (g/L) to moles per liter (mol/L):
0.72 g/L / 114.07 g/mol ≈ 0.00631 mol/L
Therefore, the molarity of glucose in blood is approximately 0.00631 M.
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If the concentration of glucose (C6H12O6) in blood is 0.72 g L-1, the molarity of glucose in blood is _______ × 10-3M. (Nearest integer)(Given: Atomic mass of C = 12, H = 1, O = 16 u)Correct answer is '4'. Can you explain this answer?
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