JEE Exam > JEE Questions > If the concentration of glucose (C6H12O6) in ...
Start Learning for Free
If the concentration of glucose (C6H12O6) in blood is 0.72 g L-1, the molarity of glucose in blood is _______ × 10-3 M. (Nearest integer)
(Given: Atomic mass of C = 12, H = 1, O = 16 u)
(Given: Atomic mass of C = 12, H = 1, O = 16 u)
Correct answer is '4'. Can you explain this answer?
| FREE This question is part of | Download PDF Attempt this Test |
Most Upvoted Answer
If the concentration of glucose (C6H12O6) in blood is 0.72 g L-1, the ...
To find the molarity of glucose in blood, we need to convert the concentration from grams per liter (g/L) to moles per liter (mol/L or M).
First, we need to determine the molar mass of glucose (C6H12O6):
1 carbon atom (C) has a molar mass of 12.01 g/mol
6 hydrogen atoms (H) have a molar mass of 1.01 g/mol each, so a total of 6.06 g/mol
6 oxygen atoms (O) have a molar mass of 16.00 g/mol each, so a total of 96.00 g/mol
Adding these together, we get:
12.01 g/mol (C) + 6.06 g/mol (H) + 96.00 g/mol (O) = 114.07 g/mol
Now, we can convert the concentration from grams per liter (g/L) to moles per liter (mol/L):
0.72 g/L / 114.07 g/mol ≈ 0.00631 mol/L
Therefore, the molarity of glucose in blood is approximately 0.00631 M.
First, we need to determine the molar mass of glucose (C6H12O6):
1 carbon atom (C) has a molar mass of 12.01 g/mol
6 hydrogen atoms (H) have a molar mass of 1.01 g/mol each, so a total of 6.06 g/mol
6 oxygen atoms (O) have a molar mass of 16.00 g/mol each, so a total of 96.00 g/mol
Adding these together, we get:
12.01 g/mol (C) + 6.06 g/mol (H) + 96.00 g/mol (O) = 114.07 g/mol
Now, we can convert the concentration from grams per liter (g/L) to moles per liter (mol/L):
0.72 g/L / 114.07 g/mol ≈ 0.00631 mol/L
Therefore, the molarity of glucose in blood is approximately 0.00631 M.
Free Test
FREE
| Start Free Test |
Community Answer
If the concentration of glucose (C6H12O6) in blood is 0.72 g L-1, the ...
Attention JEE Students!
To make sure you are not studying endlessly, EduRev has designed JEE study material, with Structured Courses, Videos, & Test Series. Plus get personalized analysis, doubt solving and improvement plans to achieve a great score in JEE.
|
Explore Courses for JEE exam
|
|
Similar JEE Doubts
Top Courses for JEEView all
If the concentration of glucose (C6H12O6) in blood is 0.72 g L-1, the molarity of glucose in blood is _______ × 10-3M. (Nearest integer)(Given: Atomic mass of C = 12, H = 1, O = 16 u)Correct answer is '4'. Can you explain this answer?
Question Description
If the concentration of glucose (C6H12O6) in blood is 0.72 g L-1, the molarity of glucose in blood is _______ × 10-3M. (Nearest integer)(Given: Atomic mass of C = 12, H = 1, O = 16 u)Correct answer is '4'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about If the concentration of glucose (C6H12O6) in blood is 0.72 g L-1, the molarity of glucose in blood is _______ × 10-3M. (Nearest integer)(Given: Atomic mass of C = 12, H = 1, O = 16 u)Correct answer is '4'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for If the concentration of glucose (C6H12O6) in blood is 0.72 g L-1, the molarity of glucose in blood is _______ × 10-3M. (Nearest integer)(Given: Atomic mass of C = 12, H = 1, O = 16 u)Correct answer is '4'. Can you explain this answer?.
If the concentration of glucose (C6H12O6) in blood is 0.72 g L-1, the molarity of glucose in blood is _______ × 10-3M. (Nearest integer)(Given: Atomic mass of C = 12, H = 1, O = 16 u)Correct answer is '4'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about If the concentration of glucose (C6H12O6) in blood is 0.72 g L-1, the molarity of glucose in blood is _______ × 10-3M. (Nearest integer)(Given: Atomic mass of C = 12, H = 1, O = 16 u)Correct answer is '4'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for If the concentration of glucose (C6H12O6) in blood is 0.72 g L-1, the molarity of glucose in blood is _______ × 10-3M. (Nearest integer)(Given: Atomic mass of C = 12, H = 1, O = 16 u)Correct answer is '4'. Can you explain this answer?.
Solutions for If the concentration of glucose (C6H12O6) in blood is 0.72 g L-1, the molarity of glucose in blood is _______ × 10-3M. (Nearest integer)(Given: Atomic mass of C = 12, H = 1, O = 16 u)Correct answer is '4'. Can you explain this answer? in English & in Hindi are available as part of our courses for JEE.
Download more important topics, notes, lectures and mock test series for JEE Exam by signing up for free.
Here you can find the meaning of If the concentration of glucose (C6H12O6) in blood is 0.72 g L-1, the molarity of glucose in blood is _______ × 10-3M. (Nearest integer)(Given: Atomic mass of C = 12, H = 1, O = 16 u)Correct answer is '4'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of
If the concentration of glucose (C6H12O6) in blood is 0.72 g L-1, the molarity of glucose in blood is _______ × 10-3M. (Nearest integer)(Given: Atomic mass of C = 12, H = 1, O = 16 u)Correct answer is '4'. Can you explain this answer?, a detailed solution for If the concentration of glucose (C6H12O6) in blood is 0.72 g L-1, the molarity of glucose in blood is _______ × 10-3M. (Nearest integer)(Given: Atomic mass of C = 12, H = 1, O = 16 u)Correct answer is '4'. Can you explain this answer? has been provided alongside types of If the concentration of glucose (C6H12O6) in blood is 0.72 g L-1, the molarity of glucose in blood is _______ × 10-3M. (Nearest integer)(Given: Atomic mass of C = 12, H = 1, O = 16 u)Correct answer is '4'. Can you explain this answer? theory, EduRev gives you an
ample number of questions to practice If the concentration of glucose (C6H12O6) in blood is 0.72 g L-1, the molarity of glucose in blood is _______ × 10-3M. (Nearest integer)(Given: Atomic mass of C = 12, H = 1, O = 16 u)Correct answer is '4'. Can you explain this answer? tests, examples and also practice JEE tests.
|
|
Explore Courses for JEE exam
|
|
Suggested Free Tests
Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
|
© EduRev
|
Education Revolution
|
|
Signup to see your scores
go up within 7 days!
Access 1000+ FREE Docs, Videos and Tests
Takes less than 10 seconds to signup