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An average person needs about 10,000 kJ energy per day. The amount of glucose (molar mass = 180.0 g mol-1) needed to meet this energy requirement is ________________ g.
(Nearest integer)
(Use: ΔCH (glucose) = -2700 kJ mol-1)
    Correct answer is '667'. Can you explain this answer?
    Most Upvoted Answer
    An average person needs about 10,000 kJ energy per day. The amount of ...
    1 kJ = 1000 J, 1 J = 1 kg m^2 s^-2, 1 cal = 4.184 J, 1 cal = 4.184 J, 1 kcal = 1000 cal.

    First, let's convert 10,000 kJ to cal:
    10,000 kJ = 10,000 * 1000 cal = 10,000,000 cal

    Now, let's convert cal to J:
    10,000,000 cal = 10,000,000 * 4.184 J = 41,840,000 J

    Next, let's convert J to kg m^2 s^-2:
    41,840,000 J = 41,840,000 * 1 kg m^2 s^-2 = 41,840,000 kg m^2 s^-2

    Finally, let's convert kg m^2 s^-2 to g:
    41,840,000 kg m^2 s^-2 = 41,840,000 g

    Since the molar mass of glucose is 180.0 g/mol, we can calculate the amount of glucose needed:
    41,840,000 g / 180.0 g/mol = 232,444.44 mol

    Rounding to the nearest integer, the amount of glucose needed to meet the energy requirement is approximately 232,444 g.
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    Community Answer
    An average person needs about 10,000 kJ energy per day. The amount of ...
    Energy released due to combustion of 1 mol Glucose = 2700kJ
    2700 kJ requires 180g of glucose
    Hence 1kJ requires 180/2700g of Glucose
    10,000 kJ requires 18/2700 x 10,000g of Glucose
    = 667 g
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    An average person needs about 10,000 kJ energy per day. The amount of glucose (molar mass = 180.0 g mol-1) needed to meet this energy requirement is ________________ g.(Nearest integer)(Use:ΔCH (glucose) = -2700 kJ mol-1)Correct answer is '667'. Can you explain this answer?
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