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Consider a disk pack with 16 surfaces, 128 tracks per surface and 256 sectors per track. 512 bytes of data are stores in a bit serial manner in a sector. The capacity of the disk pack and the number of bits required to specify a particular sector in the disk are respectively
  • a)
    256 Mbyte, 19 bits
  • b)
    256 Mbyte, 28 bit
  • c)
    512 Mbyte, 20 bits
  • d)
    64 Gbyte, 28 bits
Correct answer is option 'A'. Can you explain this answer?
Most Upvoted Answer
Consider a disk pack with 16 surfaces, 128 tracks per surface and 256 ...
Capacity of the Disk Pack:

Given:
- Number of surfaces = 16
- Number of tracks per surface = 128
- Number of sectors per track = 256
- Data stored in a sector = 512 bytes

To calculate the capacity of the disk pack, we need to multiply the number of surfaces, tracks per surface, sectors per track, and the data stored in a sector.

Capacity of the disk pack = Number of surfaces × Number of tracks per surface × Number of sectors per track × Data stored in a sector

Capacity of the disk pack = 16 × 128 × 256 × 512 bytes

To convert bytes to megabytes, we divide the result by 1,048,576 (1 MB = 1,048,576 bytes).

Capacity of the disk pack = (16 × 128 × 256 × 512) / 1,048,576 MB

Calculating this equation gives us:

Capacity of the disk pack = 256 MB

Number of Bits to Specify a Sector:

Given:
- Number of sectors per track = 256

To calculate the number of bits required to specify a particular sector in the disk, we need to find the minimum number of bits required to represent 256 sectors.

The minimum number of bits required to represent n sectors is given by the formula:

Number of bits = log2(n)

Number of bits = log2(256)

Using a calculator, we find:

Number of bits = 8 bits

Therefore, the number of bits required to specify a particular sector in the disk is 8 bits.

Conclusion:

The capacity of the disk pack is 256 Mbyte and the number of bits required to specify a particular sector in the disk is 8 bits. Therefore, the correct answer is option A: 256 Mbyte, 19 bits.
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Community Answer
Consider a disk pack with 16 surfaces, 128 tracks per surface and 256 ...
Capacity of the disk = 16 surfaces X 128 tracks X 256 sectors X 512 bytes = 256 Mbytes. To calculate number of bits required to access a sector, we need to know total number of sectors. Total number of sectors = 16 surfaces X 128 tracks X 256 sectors = 2^19 So the number of bits required to access a sector is 19. Option (A) is correct.
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Consider a disk pack with 16 surfaces, 128 tracks per surface and 256 sectors per track. 512 bytes of data are stores in a bit serial manner in a sector. The capacity of the disk pack and the number of bits required to specify a particular sector in the disk are respectivelya)256 Mbyte, 19 bitsb)256 Mbyte, 28 bitc)512 Mbyte, 20 bitsd)64 Gbyte, 28 bitsCorrect answer is option 'A'. Can you explain this answer?
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