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Consider a disk pack with 16 surfaces, 128 tracks per surface and 256 sectors per track. 512 bytes of data is stored in a bit serial manner in a sector. The capacity of the disk pack and the number of bits required to specify a particular sector in the disk respectively
are:
- a)256 Mbytes, 19 bits
- b)256 Mbytes, 28 bits
- c)512 Mbytes, 20 bits
- d)64 Gbytes, 28 bits
Correct answer is option 'A'. Can you explain this answer?
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Most Upvoted Answer
Consider a disk pack with 16 surfaces, 128 tracks per surface and 256 ...
Capacity of the disk pack:
The capacity of the disk pack can be calculated by multiplying the number of surfaces, tracks per surface, sectors per track, and the number of bytes per sector.
Given:
- Number of surfaces = 16
- Tracks per surface = 128
- Sectors per track = 256
- Bytes per sector = 512
Capacity = Number of surfaces × Tracks per surface × Sectors per track × Bytes per sector
= 16 × 128 × 256 × 512 bytes
Converting bytes to megabytes:
1 megabyte = 1,048,576 bytes
Capacity = (16 × 128 × 256 × 512) / 1,048,576 megabytes
= 256 megabytes
Therefore, the capacity of the disk pack is 256 megabytes.
Number of bits required to specify a particular sector in the disk:
To specify a particular sector, we need to consider the number of surfaces, tracks per surface, and sectors per track.
Given:
- Number of surfaces = 16
- Tracks per surface = 128
- Sectors per track = 256
To specify a sector, we need to specify the surface, track, and sector number.
Number of bits required to specify a surface = log2(number of surfaces) = log2(16) = 4 bits
Number of bits required to specify a track = log2(tracks per surface) = log2(128) = 7 bits
Number of bits required to specify a sector = log2(sectors per track) = log2(256) = 8 bits
Therefore, the number of bits required to specify a particular sector in the disk is 4 + 7 + 8 = 19 bits.
Hence, the correct answer is option A) 256 Mbytes, 19 bits.
The capacity of the disk pack can be calculated by multiplying the number of surfaces, tracks per surface, sectors per track, and the number of bytes per sector.
Given:
- Number of surfaces = 16
- Tracks per surface = 128
- Sectors per track = 256
- Bytes per sector = 512
Capacity = Number of surfaces × Tracks per surface × Sectors per track × Bytes per sector
= 16 × 128 × 256 × 512 bytes
Converting bytes to megabytes:
1 megabyte = 1,048,576 bytes
Capacity = (16 × 128 × 256 × 512) / 1,048,576 megabytes
= 256 megabytes
Therefore, the capacity of the disk pack is 256 megabytes.
Number of bits required to specify a particular sector in the disk:
To specify a particular sector, we need to consider the number of surfaces, tracks per surface, and sectors per track.
Given:
- Number of surfaces = 16
- Tracks per surface = 128
- Sectors per track = 256
To specify a sector, we need to specify the surface, track, and sector number.
Number of bits required to specify a surface = log2(number of surfaces) = log2(16) = 4 bits
Number of bits required to specify a track = log2(tracks per surface) = log2(128) = 7 bits
Number of bits required to specify a sector = log2(sectors per track) = log2(256) = 8 bits
Therefore, the number of bits required to specify a particular sector in the disk is 4 + 7 + 8 = 19 bits.
Hence, the correct answer is option A) 256 Mbytes, 19 bits.
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Community Answer
Consider a disk pack with 16 surfaces, 128 tracks per surface and 256 ...
Number of surfaces = 16
Tracks = 16 × 128 × 256 = 24 × 27 × 28
Number of bits required by a sector = 219
So, 19 lines are required to address all the sectors.
Bytes = 219 × 512 B = 219 × 29 = 228
Bytes = 256 MB
Tracks = 16 × 128 × 256 = 24 × 27 × 28
Number of bits required by a sector = 219
So, 19 lines are required to address all the sectors.
Bytes = 219 × 512 B = 219 × 29 = 228
Bytes = 256 MB
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Consider a disk pack with 16 surfaces, 128 tracks per surface and 256 sectors per track. 512 bytes of data is stored in a bit serial manner in a sector. The capacity of the disk pack and the number of bits required to specify a particular sector in the disk respectivelyare:a)256 Mbytes, 19 bitsb)256 Mbytes, 28 bitsc)512 Mbytes, 20 bitsd)64 Gbytes, 28 bitsCorrect answer is option 'A'. Can you explain this answer?
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Consider a disk pack with 16 surfaces, 128 tracks per surface and 256 sectors per track. 512 bytes of data is stored in a bit serial manner in a sector. The capacity of the disk pack and the number of bits required to specify a particular sector in the disk respectivelyare:a)256 Mbytes, 19 bitsb)256 Mbytes, 28 bitsc)512 Mbytes, 20 bitsd)64 Gbytes, 28 bitsCorrect answer is option 'A'. Can you explain this answer? for Computer Science Engineering (CSE) 2024 is part of Computer Science Engineering (CSE) preparation. The Question and answers have been prepared according to the Computer Science Engineering (CSE) exam syllabus. Information about Consider a disk pack with 16 surfaces, 128 tracks per surface and 256 sectors per track. 512 bytes of data is stored in a bit serial manner in a sector. The capacity of the disk pack and the number of bits required to specify a particular sector in the disk respectivelyare:a)256 Mbytes, 19 bitsb)256 Mbytes, 28 bitsc)512 Mbytes, 20 bitsd)64 Gbytes, 28 bitsCorrect answer is option 'A'. Can you explain this answer? covers all topics & solutions for Computer Science Engineering (CSE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Consider a disk pack with 16 surfaces, 128 tracks per surface and 256 sectors per track. 512 bytes of data is stored in a bit serial manner in a sector. The capacity of the disk pack and the number of bits required to specify a particular sector in the disk respectivelyare:a)256 Mbytes, 19 bitsb)256 Mbytes, 28 bitsc)512 Mbytes, 20 bitsd)64 Gbytes, 28 bitsCorrect answer is option 'A'. Can you explain this answer?.
Consider a disk pack with 16 surfaces, 128 tracks per surface and 256 sectors per track. 512 bytes of data is stored in a bit serial manner in a sector. The capacity of the disk pack and the number of bits required to specify a particular sector in the disk respectivelyare:a)256 Mbytes, 19 bitsb)256 Mbytes, 28 bitsc)512 Mbytes, 20 bitsd)64 Gbytes, 28 bitsCorrect answer is option 'A'. Can you explain this answer? for Computer Science Engineering (CSE) 2024 is part of Computer Science Engineering (CSE) preparation. The Question and answers have been prepared according to the Computer Science Engineering (CSE) exam syllabus. Information about Consider a disk pack with 16 surfaces, 128 tracks per surface and 256 sectors per track. 512 bytes of data is stored in a bit serial manner in a sector. The capacity of the disk pack and the number of bits required to specify a particular sector in the disk respectivelyare:a)256 Mbytes, 19 bitsb)256 Mbytes, 28 bitsc)512 Mbytes, 20 bitsd)64 Gbytes, 28 bitsCorrect answer is option 'A'. Can you explain this answer? covers all topics & solutions for Computer Science Engineering (CSE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Consider a disk pack with 16 surfaces, 128 tracks per surface and 256 sectors per track. 512 bytes of data is stored in a bit serial manner in a sector. The capacity of the disk pack and the number of bits required to specify a particular sector in the disk respectivelyare:a)256 Mbytes, 19 bitsb)256 Mbytes, 28 bitsc)512 Mbytes, 20 bitsd)64 Gbytes, 28 bitsCorrect answer is option 'A'. Can you explain this answer?.
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