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A silicon bar is doped with 1017 arsenic atoms /cm3. The equilibrium hole concentration at 300k and the location of the Fermi level (EF) of sample relative to intrinsic Fermi level (EFi) are
(Given, ni = 1.5 × 1010/cm3 )
  • a)
    2.25×103 /cm3and 0.4 eV up respectively
  • b)
    2.25×104 /cm3and 0.6 eV up respectively
  • c)
    2.25 ×103 /cm3 and 0.4 eV down respectively
  • d)
    2.25 ×104 /cm3 and 0.4 eV down respectively
Correct answer is option 'A'. Can you explain this answer?
Most Upvoted Answer
A silicon bar is doped with 1017 arsenic atoms /cm3. The equilibrium ...
Equilibrium Hole Concentration and Fermi Level of Doped Silicon Bar

Equilibrium Hole Concentration Calculation

- Given: Doping concentration of arsenic atoms (Na) = 1017 /cm3, Intrinsic carrier concentration (ni) = 1.5 × 1010 /cm3, Temperature (T) = 300 K
- To calculate equilibrium hole concentration (p), we use the equation:
p = ni2 / Na
- Substituting the given values, we get:
p = (1.5 × 1010)2 / 1017 = 2.25 × 103 /cm3
- Therefore, the equilibrium hole concentration at 300 K is 2.25 × 103 /cm3.

Fermi Level Calculation

- The location of the Fermi level (EF) of the doped silicon bar relative to the intrinsic Fermi level (EFi) depends on the type of doping (n- or p-type) and the doping concentration.
- Since the doping concentration is given as Na = 1017 /cm3, which is greater than ni, we can assume that the silicon bar is n-type doped.
- The location of EF relative to EFi for n-type doping is given by:
EF - EFi = kBT ln(Na / ni)
- Substituting the given values, we get:
EF - EFi = (8.62 × 10-5 eV/K) × (300 K) × ln(1017 / 1.5 × 1010)
EF - EFi = 0.4 eV up
- Therefore, the location of the Fermi level (EF) of the doped silicon bar relative to the intrinsic Fermi level (EFi) is 0.4 eV up.

Final Answer

- The equilibrium hole concentration at 300 K is 2.25 × 103 /cm3 and the location of the Fermi level (EF) of the doped silicon bar relative to the intrinsic Fermi level (EFi) is 0.4 eV up.
- Hence, the correct answer is option 'A'.
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Community Answer
A silicon bar is doped with 1017 arsenic atoms /cm3. The equilibrium ...
As silicon bar is doped with 1017 arsenic atoms /cm3 so,
ND = 1017/cm3
therefore, n = 1017/cm3
Given, ni = 1.5 × 1010/cm3
Now, hole concentration, p = n2f/n
= 2.25 × 103/cm3
For n -type material,
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A silicon bar is doped with 1017 arsenic atoms /cm3. The equilibrium hole concentration at 300k and the location of the Fermi level (EF) of sample relative to intrinsic Fermi level (EFi) are(Given, ni = 1.5 × 1010/cm3 )a)2.25×103 /cm3and 0.4 eV up respectivelyb)2.25×104 /cm3and 0.6 eV up respectivelyc)2.25 ×103 /cm3 and 0.4 eV down respectivelyd)2.25 ×104 /cm3 and 0.4 eV down respectivelyCorrect answer is option 'A'. Can you explain this answer?
Question Description
A silicon bar is doped with 1017 arsenic atoms /cm3. The equilibrium hole concentration at 300k and the location of the Fermi level (EF) of sample relative to intrinsic Fermi level (EFi) are(Given, ni = 1.5 × 1010/cm3 )a)2.25×103 /cm3and 0.4 eV up respectivelyb)2.25×104 /cm3and 0.6 eV up respectivelyc)2.25 ×103 /cm3 and 0.4 eV down respectivelyd)2.25 ×104 /cm3 and 0.4 eV down respectivelyCorrect answer is option 'A'. Can you explain this answer? for Electronics and Communication Engineering (ECE) 2024 is part of Electronics and Communication Engineering (ECE) preparation. The Question and answers have been prepared according to the Electronics and Communication Engineering (ECE) exam syllabus. Information about A silicon bar is doped with 1017 arsenic atoms /cm3. The equilibrium hole concentration at 300k and the location of the Fermi level (EF) of sample relative to intrinsic Fermi level (EFi) are(Given, ni = 1.5 × 1010/cm3 )a)2.25×103 /cm3and 0.4 eV up respectivelyb)2.25×104 /cm3and 0.6 eV up respectivelyc)2.25 ×103 /cm3 and 0.4 eV down respectivelyd)2.25 ×104 /cm3 and 0.4 eV down respectivelyCorrect answer is option 'A'. Can you explain this answer? covers all topics & solutions for Electronics and Communication Engineering (ECE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A silicon bar is doped with 1017 arsenic atoms /cm3. The equilibrium hole concentration at 300k and the location of the Fermi level (EF) of sample relative to intrinsic Fermi level (EFi) are(Given, ni = 1.5 × 1010/cm3 )a)2.25×103 /cm3and 0.4 eV up respectivelyb)2.25×104 /cm3and 0.6 eV up respectivelyc)2.25 ×103 /cm3 and 0.4 eV down respectivelyd)2.25 ×104 /cm3 and 0.4 eV down respectivelyCorrect answer is option 'A'. Can you explain this answer?.
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