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Consider an undirected random graph of eight vertices. The probability that there is an edge between a pair of vertices is 1/2. What is the expected number of unordered cycles of length three?
  • a)
    1/8
  • b)
    1
  • c)
    7
  • d)
    8
Correct answer is option 'C'. Can you explain this answer?
Most Upvoted Answer
Consider an undirected random graph of eight vertices. The probability...
A cycle of length 3 can be formed with 3 vertices. There can be total 8C3 ways to pick 3 vertices from 8. The probability that there is an edge between two vertices is 1/2. So expected number of unordered cycles of length 3 = (8C3)*(1/2)3 = 7
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Community Answer
Consider an undirected random graph of eight vertices. The probability...
Expected Number of Unordered Cycles of Length Three in a Random Graph

Understanding the Problem:
In an undirected random graph of eight vertices where the probability of an edge between any pair of vertices is 1/2, we need to find the expected number of unordered cycles of length three.

Solution Approach:
To find the expected number of unordered cycles of length three in the graph, we need to consider all possible sets of three vertices and calculate the probability of forming a cycle among them.

Calculating the Probability of Forming a Cycle:
- For a cycle of length three, we need three vertices connected in a cyclic manner.
- The probability of forming an edge between any two vertices is 1/2.
- Hence, the probability of forming a cycle among three vertices is (1/2) * (1/2) * (1/2) = 1/8.

Calculating the Expected Number of Cycles:
- There are a total of 8 choose 3 = 56 ways to select three vertices from eight.
- Each set of three vertices has a probability of 1/8 to form a cycle.
- Therefore, the expected number of cycles of length three can be calculated as 56 * 1/8 = 7.

Conclusion:
The expected number of unordered cycles of length three in the given random graph of eight vertices with a probability of 1/2 for any edge is 7.
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