A tall chimney releases 20 kg/s of smoke into a steady, uniform wind of speed 10 m/s. Assuming a diffusion coefficient of .01 m 2 /s, and the density of air to be 1.225 kg/m3 : a) Derive an expression for the decay of the peak (centerline) concentration with distance downwind b) Compute the peak concentration 1 and 10 km downwind c) What is the width of the smoke plume at 1 and 10 km downwind?

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A tall chimney releases 20 kg/s of smoke into a steady, uniform wind of speed 10 m/s. Assuming a diffusion coefficient of .01 m 2 /s, and the density of air to be 1.225 kg/m3 : a) Derive an expression for the decay of the peak (centerline) concentration with distance downwind b) Compute the peak concentration 1 and 10 km downwind c) What is the width of the smoke plume at 1 and 10 km downwind?

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The rate of chemical reaction at a particular temperature is proportional to the product of the molar concentration of reactants with each concentration term raised to the power equal to the number of molecules of the respective reactant taking part in the reaction. aA + bB products, rate of reaction a [Aka [Bib = k [Aka [Bib, where k is the rate constant of the reaction.EQUILIBRIUM CONSTANT (k) For a general reaction aA + bB = cC + dD, forward rate rf = kf [A]a [B]b, backward rate rb = kb [Cicpyi ,concentrations of reactants products at equilibrium are related bywhere all theconcentrations are expressed in mole/liter.In the expression of equilibrium constant those components are kept whose concentration changes with time.If equilibrium is estabilished by taking all the components in the reaction then to predict the direction of reactions we calculate the reaction quotient (Q).The values of expression at any time during reaction is called reaction quotient if Q Kc reaction proceed in backward direction until equilibrium in reached if Q Kc reaction will proceed in forward direction until equilibrium is established if Q = KC Reaction is at equilibriumQ.When C,H5OH and CH3COOH are mixed in equivalent proportion equilibrium is reached when 2/3 of acid and alcohol are used. How much ester will be present when 2 moles of acid were to react with 2 moles of alcohol? .

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The rate of chemical reaction at a particular temperature is proportional to the product of the molar concentration of reactants with each concentration term raised to the power equal to the number of molecules of the respective reactant taking part in the reaction. aA + bB products, rate of reaction a [Aka [Bib = k [Aka [Bib, where k is the rate constant of the reaction.EQUILIBRIUM CONSTANT (k) For a general reaction aA + bB = cC + dD, forward rate rf = kf [A]a [B]b, backward rate rb = kb [Cicpyi ,concentrations of reactants products at equilibrium are related bywhere all theconcentrations are expressed in mole/liter.In the expression of equilibrium constant those components are kept whose concentration changes with time.If equilibrium is estabilished by taking all the components in the reaction then to predict the direction of reactions we calculate the reaction quotient (Q).The values of expression at any time during reaction is called reaction quotient if Q Kc reaction proceed in backward direction until equilibrium in reached if Q Kc reaction will proceed in forward direction until equilibrium is established if Q = KC Reaction is at equilibriumq.Above homogeneous reaction is carried out in a 2 litre container at a particular temperature by taking 1 mole each of A, B, C and D respectively. If Kc for the reaction is then equilibrium concentration of C is

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A tall chimney releases 20 kg/s of smoke into a steady, uniform wind of speed 10 m/s. Assuming a diffusion coefficient of .01 m 2 /s, and the density of air to be 1.225 kg/m3 : a) Derive an expression for the decay of the peak (centerline) concentration with distance downwind b) Compute the peak concentration 1 and 10 km downwind c) What is the width of the smoke plume at 1 and 10 km downwind? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about A tall chimney releases 20 kg/s of smoke into a steady, uniform wind of speed 10 m/s. Assuming a diffusion coefficient of .01 m 2 /s, and the density of air to be 1.225 kg/m3 : a) Derive an expression for the decay of the peak (centerline) concentration with distance downwind b) Compute the peak concentration 1 and 10 km downwind c) What is the width of the smoke plume at 1 and 10 km downwind? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A tall chimney releases 20 kg/s of smoke into a steady, uniform wind of speed 10 m/s. Assuming a diffusion coefficient of .01 m 2 /s, and the density of air to be 1.225 kg/m3 : a) Derive an expression for the decay of the peak (centerline) concentration with distance downwind b) Compute the peak concentration 1 and 10 km downwind c) What is the width of the smoke plume at 1 and 10 km downwind?.

Solutions for A tall chimney releases 20 kg/s of smoke into a steady, uniform wind of speed 10 m/s. Assuming a diffusion coefficient of .01 m 2 /s, and the density of air to be 1.225 kg/m3 : a) Derive an expression for the decay of the peak (centerline) concentration with distance downwind b) Compute the peak concentration 1 and 10 km downwind c) What is the width of the smoke plume at 1 and 10 km downwind? in English & in Hindi are available as part of our courses for JEE. Download more important topics, notes, lectures and mock test series for JEE Exam by signing up for free.

Here you can find the meaning of A tall chimney releases 20 kg/s of smoke into a steady, uniform wind of speed 10 m/s. Assuming a diffusion coefficient of .01 m 2 /s, and the density of air to be 1.225 kg/m3 : a) Derive an expression for the decay of the peak (centerline) concentration with distance downwind b) Compute the peak concentration 1 and 10 km downwind c) What is the width of the smoke plume at 1 and 10 km downwind? defined & explained in the simplest way possible. Besides giving the explanation of A tall chimney releases 20 kg/s of smoke into a steady, uniform wind of speed 10 m/s. Assuming a diffusion coefficient of .01 m 2 /s, and the density of air to be 1.225 kg/m3 : a) Derive an expression for the decay of the peak (centerline) concentration with distance downwind b) Compute the peak concentration 1 and 10 km downwind c) What is the width of the smoke plume at 1 and 10 km downwind?, a detailed solution for A tall chimney releases 20 kg/s of smoke into a steady, uniform wind of speed 10 m/s. Assuming a diffusion coefficient of .01 m 2 /s, and the density of air to be 1.225 kg/m3 : a) Derive an expression for the decay of the peak (centerline) concentration with distance downwind b) Compute the peak concentration 1 and 10 km downwind c) What is the width of the smoke plume at 1 and 10 km downwind? has been provided alongside types of A tall chimney releases 20 kg/s of smoke into a steady, uniform wind of speed 10 m/s. Assuming a diffusion coefficient of .01 m 2 /s, and the density of air to be 1.225 kg/m3 : a) Derive an expression for the decay of the peak (centerline) concentration with distance downwind b) Compute the peak concentration 1 and 10 km downwind c) What is the width of the smoke plume at 1 and 10 km downwind? theory, EduRev gives you an ample number of questions to practice A tall chimney releases 20 kg/s of smoke into a steady, uniform wind of speed 10 m/s. Assuming a diffusion coefficient of .01 m 2 /s, and the density of air to be 1.225 kg/m3 : a) Derive an expression for the decay of the peak (centerline) concentration with distance downwind b) Compute the peak concentration 1 and 10 km downwind c) What is the width of the smoke plume at 1 and 10 km downwind? tests, examples and also practice JEE tests.

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