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For the reaction:
A(ℓ) →2B(g),
ΔU = 2.1 kcal, ΔS = 20 cal K-1 at 300 K.
Hence, ΔG in kcal is _________.(Answer up to one decimal place)
A(ℓ) →2B(g),
ΔU = 2.1 kcal, ΔS = 20 cal K-1 at 300 K.
Hence, ΔG in kcal is _________.(Answer up to one decimal place)
Correct answer is '-2.7'. Can you explain this answer?
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Most Upvoted Answer
For the reaction:A() →2B(g),ΔU = 2.1 kcal, ΔS = 20 ca...
To provide a complete answer, I would need to know the full chemical equation for the reaction. Without the information about the reactant and product, it is not possible to determine the specific details of the reaction.
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Community Answer
For the reaction:A() →2B(g),ΔU = 2.1 kcal, ΔS = 20 ca...
We know:
ΔG = ΔH - TΔS
ΔH = ΔU + 2RT
Thus, we have:
ΔG = ΔU + 2RT - TΔS
On putting the given values, we get:
ΔG = 2.1 + 2 × 2 × 300 × 10-3 - 300 × 20 × 10-3
ΔG = 2.1 + 4 × 300 × 10-3 - 300 × 20 × 10-3
ΔG = 2.1 + 1200 × 10-3 - 6000 × 10-3
ΔG = 2.1 + 1.2 - 6
ΔG = 3.3 - 6
ΔG = -2.7 kcal
ΔG = ΔH - TΔS
ΔH = ΔU + 2RT
Thus, we have:
ΔG = ΔU + 2RT - TΔS
On putting the given values, we get:
ΔG = 2.1 + 2 × 2 × 300 × 10-3 - 300 × 20 × 10-3
ΔG = 2.1 + 4 × 300 × 10-3 - 300 × 20 × 10-3
ΔG = 2.1 + 1200 × 10-3 - 6000 × 10-3
ΔG = 2.1 + 1.2 - 6
ΔG = 3.3 - 6
ΔG = -2.7 kcal
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For the reaction:A() →2B(g),ΔU = 2.1 kcal, ΔS = 20 cal K-1 at 300 K.Hence, ΔG in kcal is _________.(Answer up to one decimal place)Correct answer is '-2.7'. Can you explain this answer?
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For the reaction:A() →2B(g),ΔU = 2.1 kcal, ΔS = 20 cal K-1 at 300 K.Hence, ΔG in kcal is _________.(Answer up to one decimal place)Correct answer is '-2.7'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about For the reaction:A() →2B(g),ΔU = 2.1 kcal, ΔS = 20 cal K-1 at 300 K.Hence, ΔG in kcal is _________.(Answer up to one decimal place)Correct answer is '-2.7'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for For the reaction:A() →2B(g),ΔU = 2.1 kcal, ΔS = 20 cal K-1 at 300 K.Hence, ΔG in kcal is _________.(Answer up to one decimal place)Correct answer is '-2.7'. Can you explain this answer?.
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