Given data:
- Dipole moment of HBrHBr = 1.6 × 10^(-30) C-m
- Inter-atomic spacing = 1 Å

Concept:
The percentage of ionic character in a molecule can be determined using the relationship between dipole moment and inter-atomic spacing.

Calculations:
The dipole moment (μ) of a molecule can be calculated using the formula:

μ = q × d

Where:
- μ is the dipole moment in C-m
- q is the charge in Coloumb (C)
- d is the distance between the charges in meters (m)

In the case of HBrHBr, the molecule consists of two HBr molecules bonded together. The dipole moment of each HBr molecule is the same and given as 1.6 × 10^(-30) C-m.

The inter-atomic spacing between the two HBr molecules is given as 1 Å. We need to convert this to meters.

1 Å = 1 × 10^(-10) m

Now, we can calculate the charge (q) in Coloumb using the formula:

q = μ / d

Substituting the given values:

q = (1.6 × 10^(-30) C-m) / (1 × 10^(-10) m)
= 1.6 × 10^(-20) C

The charge (q) represents the partial positive and negative charges on the atoms in the molecule. The total charge on the molecule (Q) is the sum of these partial charges.

Q = 2q
= 2 × (1.6 × 10^(-20) C)
= 3.2 × 10^(-20) C

Calculation of ionic character:
The percentage of ionic character in a molecule can be determined using the formula:

Ionic character (%) = (Q / e) × 100

Where:
- Q is the total charge on the molecule in Coloumb (C)
- e is the charge of an electron in Coloumb (C)

The charge of an electron (e) is given as 1.6 × 10^(-19) C.

Substituting the values:

Ionic character (%) = (3.2 × 10^(-20) C / 1.6 × 10^(-19) C) × 100
= 0.2 × 100
= 20%

However, we are asked to give the answer as the nearest integer. Since the calculated value is 20%, the nearest integer is 20, which is different from the given correct answer of 10.

This suggests that there may be an error in the given data or calculations. It would be advisable to recheck the data and calculations to ensure accuracy.