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How many ordered pairs of natural numbers satisfy the inequality 8x + 2y ≤ 24?  
  • a)
    8
  • b)
    12
  • c)
    10
  • d)
    15
Correct answer is option 'B'. Can you explain this answer?
Most Upvoted Answer
How many ordered pairs of natural numbers satisfy the inequality 8x + ...
The inequality 8x - 2y < 40="" can="" be="" rewritten="" as="" 4x="" -="" y="" />< />

Let's consider the possible values for x and y.

When x = 1, the inequality becomes 4(1) - y < 20,="" which="" simplifies="" to="" -y="" />< 16.="" since="" y="" is="" a="" natural="" number,="" the="" only="" possible="" value="" is="" y="" />

When x = 2, the inequality becomes 4(2) - y < 20,="" which="" simplifies="" to="" 8="" -="" y="" />< 20.="" solving="" for="" y,="" we="" get="" y="" /> -12. Since y is a natural number, the possible values for y are 1, 2, 3, ..., 11, which is a total of 11 values.

Similarly, when x = 3, we have y > -8, giving us a total of 9 possible values for y.

Continuing this pattern, we find that when x = 1, there is 1 possible value for y. When x = 2, there are 11 possible values for y. When x = 3, there are 9 possible values for y. And so on.

Therefore, the total number of ordered pairs of natural numbers that satisfy the inequality is 1 + 11 + 9 + ... = 1 + 11 + 9 + 7 + 5 + 3 + 1 = 37.
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How many ordered pairs of natural numbers satisfy the inequality 8x + 2y ≤ 24?a)8b)12c)10d)15Correct answer is option 'B'. Can you explain this answer?
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