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Which of the following compounds will show geometrical isomerism?
- a)1-Phenylpropene
- b)Propene
- c)2-Methyl-2-butene
- d)1-Butene
Correct answer is option 'A'. Can you explain this answer?
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Which of the following compounds will show geometrical isomerism?a)1-P...
Geometrical Isomerism in 1-Phenylpropene
Geometrical isomerism occurs when different spatial arrangements are possible due to restricted rotation around a double bond or ring. Let's analyze the given compounds to identify which one will exhibit geometrical isomerism:
- 1-Phenylpropene: This compound has a double bond between the first and second carbon atoms, with a phenyl group attached to the first carbon. The phenyl group restricts the rotation around the double bond, leading to the possibility of geometrical isomerism.
- Propene: It has a double bond between the first and second carbon atoms, but there are no additional substituents to restrict rotation. Therefore, it will not show geometrical isomerism.
- 2-Methyl-2-butene: This compound has a double bond between the first and second carbon atoms, with a methyl group on the second carbon. However, the presence of two identical groups on the second carbon does not lead to geometrical isomerism.
- 1-Butene: It has a double bond between the first and second carbon atoms, but there are no additional substituents to cause restricted rotation. Hence, it will not exhibit geometrical isomerism.
Therefore, the compound that will show geometrical isomerism among the given options is 1-Phenylpropene due to the presence of a phenyl group that restricts rotation around the double bond.
Geometrical isomerism occurs when different spatial arrangements are possible due to restricted rotation around a double bond or ring. Let's analyze the given compounds to identify which one will exhibit geometrical isomerism:
- 1-Phenylpropene: This compound has a double bond between the first and second carbon atoms, with a phenyl group attached to the first carbon. The phenyl group restricts the rotation around the double bond, leading to the possibility of geometrical isomerism.
- Propene: It has a double bond between the first and second carbon atoms, but there are no additional substituents to restrict rotation. Therefore, it will not show geometrical isomerism.
- 2-Methyl-2-butene: This compound has a double bond between the first and second carbon atoms, with a methyl group on the second carbon. However, the presence of two identical groups on the second carbon does not lead to geometrical isomerism.
- 1-Butene: It has a double bond between the first and second carbon atoms, but there are no additional substituents to cause restricted rotation. Hence, it will not exhibit geometrical isomerism.
Therefore, the compound that will show geometrical isomerism among the given options is 1-Phenylpropene due to the presence of a phenyl group that restricts rotation around the double bond.
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Which of the following compounds will show geometrical isomerism?a)1-P...
Geometrical isomerism is shown by the compounds having at least one C=C and the two groups attached to each carbon must be different.
Only (a) fulfills both conditions and shows geometrical isomerism.
Only (a) fulfills both conditions and shows geometrical isomerism.
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Which of the following compounds will show geometrical isomerism?a)1-Phenylpropeneb)Propenec)2-Methyl-2-butened)1-ButeneCorrect answer is option 'A'. Can you explain this answer?
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