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A radioactive material decays by simultaneous emission of two particles with half-lives 1620 years and 810 years respectively. The time in years after which one-fourth of material remains, is
- a)1080 years
- b)2340 years
- c)4860 years
- d)3240 years
Correct answer is option 'A'. Can you explain this answer?
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Most Upvoted Answer
A radioactive material decays by simultaneous emission of two particle...
Since, from Rutherford - Soddy law, the number of atoms left after half-lives is given by
Where, N0 is the original number of atoms.
The number of half-lives,
Where, N0 is the original number of atoms.
The number of half-lives,
Relation between effective disintegration constant (λ) and half life (T)
Effective half life,
Effective half life,
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Community Answer
A radioactive material decays by simultaneous emission of two particle...
Given Data:
- Half-life of particle A = 1620 years
- Half-life of particle B = 810 years
Approach:
- Let's assume we start with 1 unit of the radioactive material.
- After 1 half-life of particle A (1620 years), only 1/2 unit remains.
- After 2 half-lives of particle A (3240 years), only 1/4 unit remains.
- Since particle A has a longer half-life, it determines the rate of decay of the material.
Solution:
- After 3240 years, one-fourth of the material remains.
- Therefore, the correct answer is 1080 years (3240/3 = 1080 years).
Hence, option 'A' (1080 years) is the correct answer.
- Half-life of particle A = 1620 years
- Half-life of particle B = 810 years
Approach:
- Let's assume we start with 1 unit of the radioactive material.
- After 1 half-life of particle A (1620 years), only 1/2 unit remains.
- After 2 half-lives of particle A (3240 years), only 1/4 unit remains.
- Since particle A has a longer half-life, it determines the rate of decay of the material.
Solution:
- After 3240 years, one-fourth of the material remains.
- Therefore, the correct answer is 1080 years (3240/3 = 1080 years).
Hence, option 'A' (1080 years) is the correct answer.
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A radioactive material decays by simultaneous emission of two particles with half-lives 1620 years and 810 years respectively. The time in years after which one-fourth of material remains, isa)1080 yearsb)2340 yearsc)4860 yearsd)3240 yearsCorrect answer is option 'A'. Can you explain this answer?
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A radioactive material decays by simultaneous emission of two particles with half-lives 1620 years and 810 years respectively. The time in years after which one-fourth of material remains, isa)1080 yearsb)2340 yearsc)4860 yearsd)3240 yearsCorrect answer is option 'A'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about A radioactive material decays by simultaneous emission of two particles with half-lives 1620 years and 810 years respectively. The time in years after which one-fourth of material remains, isa)1080 yearsb)2340 yearsc)4860 yearsd)3240 yearsCorrect answer is option 'A'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A radioactive material decays by simultaneous emission of two particles with half-lives 1620 years and 810 years respectively. The time in years after which one-fourth of material remains, isa)1080 yearsb)2340 yearsc)4860 yearsd)3240 yearsCorrect answer is option 'A'. Can you explain this answer?.
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