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The resistance of a coil is 4.2Ωat 100oC and the temperature coefficient of resistance of its material is 0.004oC. Its resistance will be 4Ωata)87.5oCb)50oCc)22.5oCd)72.5oCCorrect answer is option 'A'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about The resistance of a coil is 4.2Ωat 100oC and the temperature coefficient of resistance of its material is 0.004oC. Its resistance will be 4Ωata)87.5oCb)50oCc)22.5oCd)72.5oCCorrect answer is option 'A'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The resistance of a coil is 4.2Ωat 100oC and the temperature coefficient of resistance of its material is 0.004oC. Its resistance will be 4Ωata)87.5oCb)50oCc)22.5oCd)72.5oCCorrect answer is option 'A'. Can you explain this answer?.

Solutions for The resistance of a coil is 4.2Ωat 100oC and the temperature coefficient of resistance of its material is 0.004oC. Its resistance will be 4Ωata)87.5oCb)50oCc)22.5oCd)72.5oCCorrect answer is option 'A'. Can you explain this answer? in English & in Hindi are available as part of our courses for JEE. Download more important topics, notes, lectures and mock test series for JEE Exam by signing up for free.

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