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Find the probability that a four digit number comprising the digits 2,5,6 and 7 would be divisible by 4?
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Find the probability that a four digit number comprising the digits 2,...
Solution:

To find the probability that a four-digit number comprising the digits 2, 5, 6, and 7 would be divisible by 4, we need to follow the steps given below:

Step 1: Find the total number of ways to form a four-digit number using the digits 2, 5, 6, and 7.

We can use the permutation formula to find the total number of ways to form a four-digit number using four distinct digits. Therefore, the total number of ways to form a four-digit number using the digits 2, 5, 6, and 7 is given by:

4P4 = 4! / (4-4)! = 24

Therefore, there are 24 possible four-digit numbers that can be formed using the digits 2, 5, 6, and 7.

Step 2: Find the number of four-digit numbers that are divisible by 4.

A number is divisible by 4 if and only if its last two digits are divisible by 4. Therefore, we need to consider only the last two digits of each four-digit number to determine if it is divisible by 4. We can use the following cases to find the number of four-digit numbers that are divisible by 4:

Case 1: The last two digits are 2 and 6.

In this case, the first two digits can be any of the remaining two digits. Therefore, the number of four-digit numbers that are divisible by 4 with the last two digits as 2 and 6 is:

2 x 1 x 1 = 2

Case 2: The last two digits are 6 and 2.

In this case, the first two digits can be any of the remaining two digits. Therefore, the number of four-digit numbers that are divisible by 4 with the last two digits as 6 and 2 is:

2 x 1 x 1 = 2

Case 3: The last two digits are 2 and 5.

In this case, the first two digits can be any of the remaining two digits. Therefore, the number of four-digit numbers that are divisible by 4 with the last two digits as 2 and 5 is:

2 x 1 x 1 = 2

Case 4: The last two digits are 6 and 5.

In this case, the first two digits can be any of the remaining two digits. Therefore, the number of four-digit numbers that are divisible by 4 with the last two digits as 6 and 5 is:

2 x 1 x 1 = 2

Therefore, the total number of four-digit numbers that are divisible by 4 is:

2 + 2 + 2 + 2 = 8

Step 3: Find the probability that a four-digit number comprising the digits 2, 5, 6, and 7 would be divisible by 4.

The probability of an event is the number of favorable outcomes divided by the total number of possible outcomes. Therefore, the probability that a four-digit number comprising the digits 2, 5, 6, and 7 would be divisible by 4 is:

8 / 24 = 1 / 3

Therefore, the probability that a four-digit number comprising the digits 2, 5, 6, and 7 would be divisible by
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Find the probability that a four digit number comprising the digits 2,5,6 and 7 would be divisible by 4?
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Find the probability that a four digit number comprising the digits 2,5,6 and 7 would be divisible by 4? for CA Foundation 2024 is part of CA Foundation preparation. The Question and answers have been prepared according to the CA Foundation exam syllabus. Information about Find the probability that a four digit number comprising the digits 2,5,6 and 7 would be divisible by 4? covers all topics & solutions for CA Foundation 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Find the probability that a four digit number comprising the digits 2,5,6 and 7 would be divisible by 4?.
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