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A Si pnp transistor biased in the forward active mode of operation has emitter/collector doping = 1018 cm3, base doping = 1015 cm3, electron lifetime in emitter = 10 nsec, electronmobility in emitter = 1350 cm2/V-sec, hole mobility in base = 480 cm2/V-sec, hole lifetime in base = 10 sec, electrically neutral base width = 10 m, Calculate the collector-to-emitter and the collectorto-base current transfer ratios of the transistor.?
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A Si pnp transistor biased in the forward active mode of operation has...
Solution:

Given parameters:
Emitter/collector doping = 1018 cm3
Base doping = 1015 cm3
Electron lifetime in emitter = 10 nsec
Electron mobility in emitter = 1350 cm2/V-sec
Hole mobility in base = 480 cm2/V-sec
Hole lifetime in base = 10 sec
Electrically neutral base width = 10 m

To find:
Collector-to-emitter current transfer ratio (hFE)
Collector-to-base current transfer ratio (hFC)

Collector-to-emitter current transfer ratio (hFE):

The collector-to-emitter current transfer ratio (hFE) is defined as the ratio of collector current (IC) to the base current (IB) in a transistor.

hFE = IC / IB

The collector current (IC) can be calculated as:

IC = q * A * Dn * n * VCB / L

Where,
q = Charge of an electron = 1.6 x 10^-19 Coulombs
A = Area of the collector = 10^-4 cm^2
Dn = Electron diffusion coefficient = (KT/q) * mue
KT = Boltzmann constant = 1.38 x 10^-23 J/K
mue = Electron mobility in emitter = 1350 cm2/V-sec
n = Emitter doping concentration = 1018 cm^-3
VCB = Voltage between collector and base = VCE - VBE
VCE = Collector-emitter voltage
VBE = Base-emitter voltage
L = Collector thickness = 10 μm

The base current (IB) can be calculated as:

IB = q * A * Dp * p / W

Where,
Dp = Hole diffusion coefficient = (KT/q) * mup
mup = Hole mobility in base = 480 cm2/V-sec
p = Base doping concentration = 1015 cm^-3
W = Base width = 10 μm

Substituting the values, we get:

Dn = (KT/q) * mue = (1.38 x 10^-23 J/K * 1350 cm2/V-sec) / (1.6 x 10^-19 Coulombs) = 117.7 cm^2/sec
Dp = (KT/q) * mup = (1.38 x 10^-23 J/K * 480 cm2/V-sec) / (1.6 x 10^-19 Coulombs) = 40.5 cm^2/sec

IC = (1.6 x 10^-19 Coulombs) * (10^-4 cm^2) * (117.7 cm^2/sec) * (1018 cm^-3) * (VCB / 10 μm)
IB = (1.6 x 10^-19 Coulombs) * (10^-4 cm^2) * (40.5 cm^2/sec) * (1015 cm^-3) / (10 μm)

Assuming VBE = 0.7 V and VCE = 5 V, we get VCB = 4.3 V

IC = (1.6 x 10^-19 Coulombs) * (10^-4 cm^2) * (117.7 cm^2/sec) * (101
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A Si pnp transistor biased in the forward active mode of operation has emitter/collector doping = 1018 cm3, base doping = 1015 cm3, electron lifetime in emitter = 10 nsec, electronmobility in emitter = 1350 cm2/V-sec, hole mobility in base = 480 cm2/V-sec, hole lifetime in base = 10 sec, electrically neutral base width = 10 m, Calculate the collector-to-emitter and the collectorto-base current transfer ratios of the transistor.?
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A Si pnp transistor biased in the forward active mode of operation has emitter/collector doping = 1018 cm3, base doping = 1015 cm3, electron lifetime in emitter = 10 nsec, electronmobility in emitter = 1350 cm2/V-sec, hole mobility in base = 480 cm2/V-sec, hole lifetime in base = 10 sec, electrically neutral base width = 10 m, Calculate the collector-to-emitter and the collectorto-base current transfer ratios of the transistor.? for Electronics and Communication Engineering (ECE) 2024 is part of Electronics and Communication Engineering (ECE) preparation. The Question and answers have been prepared according to the Electronics and Communication Engineering (ECE) exam syllabus. Information about A Si pnp transistor biased in the forward active mode of operation has emitter/collector doping = 1018 cm3, base doping = 1015 cm3, electron lifetime in emitter = 10 nsec, electronmobility in emitter = 1350 cm2/V-sec, hole mobility in base = 480 cm2/V-sec, hole lifetime in base = 10 sec, electrically neutral base width = 10 m, Calculate the collector-to-emitter and the collectorto-base current transfer ratios of the transistor.? covers all topics & solutions for Electronics and Communication Engineering (ECE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A Si pnp transistor biased in the forward active mode of operation has emitter/collector doping = 1018 cm3, base doping = 1015 cm3, electron lifetime in emitter = 10 nsec, electronmobility in emitter = 1350 cm2/V-sec, hole mobility in base = 480 cm2/V-sec, hole lifetime in base = 10 sec, electrically neutral base width = 10 m, Calculate the collector-to-emitter and the collectorto-base current transfer ratios of the transistor.?.
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