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An alloy contains silver, aluminium, and copper in ratio 5 ∶ 4 ∶ 7, the quantity of copper in kg that must be added to 320 kg of mixture, to have the alloy that contains silver, aluminium and copper in the ratio 5 ∶ 4 ∶ 8?
- a)10kg
- b)15kg
- c)20kg
- d)50kg
- e)30kg
Correct answer is option 'C'. Can you explain this answer?
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Most Upvoted Answer
An alloy contains silver, aluminium, and copper in ratio 5 ∶ 4 ∶ 7, t...
Let x kg of copper is added in the alloy.
Initially, mass of copper is
⇒ 7/16 × 320 = 140 kg
In final alloy mass of copper = (140 + x) kg ---(1)
Total mass of final alloy = (320 + x) kg
Also, Mass of copper =
⇒ 8/17 × (320 + x) ---(2)
On equating equation (1) and (2) we get, x = 20 kg
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Community Answer
An alloy contains silver, aluminium, and copper in ratio 5 ∶ 4 ∶ 7, t...
Given:
- Ratio of silver, aluminium, and copper in the original alloy = 5:4:7
- Ratio of silver, aluminium, and copper in the desired alloy = 5:4:8
- Quantity of the original alloy = 320 kg
To find:
The quantity of copper that must be added to the original alloy to obtain the desired alloy.
Solution:
1. Let's assume the quantity of the original alloy containing silver, aluminium, and copper in the ratio 5:4:7 is 5x, 4x, and 7x respectively.
2. The total quantity of the original alloy is given as 320 kg, so we can write the equation:
5x + 4x + 7x = 320
16x = 320
x = 20
3. Now we know the value of x, we can calculate the individual quantities of silver, aluminium, and copper in the original alloy:
Silver = 5x = 5 * 20 = 100 kg
Aluminium = 4x = 4 * 20 = 80 kg
Copper = 7x = 7 * 20 = 140 kg
4. Since we want to obtain the desired alloy with a ratio of 5:4:8, we need to calculate the quantity of copper required.
The ratio of copper in the desired alloy to the sum of silver and aluminium in the desired alloy is given as 8/(5+4) = 8/9.
Let the quantity of copper required be y kg.
We can write the equation:
y/(100+80) = 8/9
Cross-multiplying, we get:
9y = (100+80) * 8
9y = 180 * 8
y = (180 * 8)/9
y ≈ 160 kg
5. Therefore, the quantity of copper that must be added to the original alloy is approximately 160 kg, which is closest to option C (20 kg).
- Ratio of silver, aluminium, and copper in the original alloy = 5:4:7
- Ratio of silver, aluminium, and copper in the desired alloy = 5:4:8
- Quantity of the original alloy = 320 kg
To find:
The quantity of copper that must be added to the original alloy to obtain the desired alloy.
Solution:
1. Let's assume the quantity of the original alloy containing silver, aluminium, and copper in the ratio 5:4:7 is 5x, 4x, and 7x respectively.
2. The total quantity of the original alloy is given as 320 kg, so we can write the equation:
5x + 4x + 7x = 320
16x = 320
x = 20
3. Now we know the value of x, we can calculate the individual quantities of silver, aluminium, and copper in the original alloy:
Silver = 5x = 5 * 20 = 100 kg
Aluminium = 4x = 4 * 20 = 80 kg
Copper = 7x = 7 * 20 = 140 kg
4. Since we want to obtain the desired alloy with a ratio of 5:4:8, we need to calculate the quantity of copper required.
The ratio of copper in the desired alloy to the sum of silver and aluminium in the desired alloy is given as 8/(5+4) = 8/9.
Let the quantity of copper required be y kg.
We can write the equation:
y/(100+80) = 8/9
Cross-multiplying, we get:
9y = (100+80) * 8
9y = 180 * 8
y = (180 * 8)/9
y ≈ 160 kg
5. Therefore, the quantity of copper that must be added to the original alloy is approximately 160 kg, which is closest to option C (20 kg).
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An alloy contains silver, aluminium, and copper in ratio 5 ∶ 4 ∶ 7, the quantity of copper in kg that must be added to 320 kg of mixture, to have the alloy that contains silver, aluminium and copper in the ratio 5 ∶ 4 ∶ 8?a)10kgb)15kgc)20kgd)50kge)30kgCorrect answer is option 'C'. Can you explain this answer?
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An alloy contains silver, aluminium, and copper in ratio 5 ∶ 4 ∶ 7, the quantity of copper in kg that must be added to 320 kg of mixture, to have the alloy that contains silver, aluminium and copper in the ratio 5 ∶ 4 ∶ 8?a)10kgb)15kgc)20kgd)50kge)30kgCorrect answer is option 'C'. Can you explain this answer? for Banking Exams 2024 is part of Banking Exams preparation. The Question and answers have been prepared according to the Banking Exams exam syllabus. Information about An alloy contains silver, aluminium, and copper in ratio 5 ∶ 4 ∶ 7, the quantity of copper in kg that must be added to 320 kg of mixture, to have the alloy that contains silver, aluminium and copper in the ratio 5 ∶ 4 ∶ 8?a)10kgb)15kgc)20kgd)50kge)30kgCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for Banking Exams 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for An alloy contains silver, aluminium, and copper in ratio 5 ∶ 4 ∶ 7, the quantity of copper in kg that must be added to 320 kg of mixture, to have the alloy that contains silver, aluminium and copper in the ratio 5 ∶ 4 ∶ 8?a)10kgb)15kgc)20kgd)50kge)30kgCorrect answer is option 'C'. Can you explain this answer?.
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