All Courses
Explore Courses UPSC Exam UPSC Test Series Free Notes EduRev Infinity Get the App Login Join for Free
Sign in Open App
CAT Exam  >  CAT Questions  >  In a 20 km long tunnel connecting two cities ... Start Learning for Free
SaveJoin the Discussion on the App
In a 20 km long tunnel connecting two cities A and B, there are three gutters. The distance between gutters 1 and 2 is half the distance between gutters 2 and 3. The distance from city A to its nearest gutter - gutter 1 - is equal to the distance of city B from gutter 3. On a particular day, the hospital in city A receives information that an accident has occurred at the third gutter. The victim can be saved only if an operation is started within 40 minutes. An ambulance starts from city A at 30 km/hr and crosses the first gutter after 5 minutes. If the driver doubles the speed after that, then what is the maximum amount of time the doctor will get to attend the patient at the hospital before starting the operation. Assume 1 minute elapses in taking the patient into and out of the ambulance.
  • a)
    4 minutes
  • b)
    2.5 minutes
  • c)
    1.5 minutes
  • d)
    The patient died before reaching the hospital.
Correct answer is option 'C'. Can you explain this answer?
FREE This question is part of
Download PDF Attempt Test
Download PDF Attempt this Test
Most Upvoted Answer
In a 20 km long tunnel connecting two cities A and B, there are three ...
Given Information:
- Distance between cities A and B: 20 km
- Three gutters in the tunnel: Gutters 1, 2, and 3
- Distance between gutter 1 and 2 = x
- Distance between gutter 2 and 3 = 2x
- Distance from city A to gutter 1 = Distance from city B to gutter 3

Calculation:
- Let's assume the distance between city A and gutter 1 is y km. So, the distance between city B and gutter 3 is also y km.
- Therefore, the total distance between city A and gutter 3 is (20 - 2y) km.
- The ambulance travels at 30 km/hr, so it covers the distance of y km in 5 minutes.
- After the first 5 minutes, the ambulance doubles its speed, covering the remaining distance at 60 km/hr.
- The time taken to cover the remaining distance of (20 - 2y) km at 60 km/hr is (20 - 2y) / 60 hours.

Time Calculation:
- Total time taken = Time taken in the first leg (5 minutes) + Time taken in the second leg ((20 - 2y) / 60 hours) + 1 minute for loading/unloading
- Total time taken = 5 minutes + (20 - 2y) / 60 hours + 1 minute

Given condition:
- The patient can be saved only if the operation is started within 40 minutes.
- Therefore, the maximum amount of time the doctor will get to attend the patient before starting the operation is 40 minutes - Total time taken.
Therefore, the maximum amount of time the doctor will get to attend the patient before starting the operation is 40 minutes - (5 minutes + (20 - 2y) / 60 hours + 1 minute) = 1.5 minutes.
Therefore, the correct answer is option C) 1.5 minutes.
Attention CAT Students!
To make sure you are not studying endlessly, EduRev has designed CAT study material, with Structured Courses, Videos, & Test Series. Plus get personalized analysis, doubt solving and improvement plans to achieve a great score in CAT.
< Previous Question Next Question >
Explore Courses for CAT exam

Similar CAT Doubts

Directions: Read the given information carefully and answer the question that follows.A spy of XYZ kingdom regularly spies between seven enemy camps that are located inside a forest, and are connected to each other by forest roads, FR–1, FR–2, FR–3, FR–4, FR–5, FR–6, and FR–7. The spy has made a map so that he can travel with ease between camps and get the useful information required. However, while travelling between any two enemy camps, the spy always chooses the route which passes through the minimum possible number of enemy camps. If two or more routes pass through the minimum number of enemy camps, he chooses the route for which the distance is also the least. The length of the forest road, directly connecting any two enemy camps, is a multiple of 10. For any pair of enemy camps, the length of a route connecting the two enemy camps and passing through the minimum possible number of enemy camps, is called a forest road stretch between the two enemy camps. The least among all the forest road stretches between two enemy camps is called the minimum forest road stretch between the two enemy camps.The following information is known about the distances between the enemy camps:1. The minimum forest road stretch between FR–4 and FR–6 is 90 miles, while the minimum forest road stretch between FR–2 and FR–6 is 30 miles.2. The highest forest road stretch between FR–1 and FR–7 is 360 miles.3. The minimum forest road stretch between FR–4 and FR–7 is 30 miles.4. The sum of the lengths of the road directly connecting FR–5 to FR–6 and that directly connecting FR–5 and FR–7 is 100 miles.5. The minimum forest road stretch between FR–7 and FR–2 is 70 miles, while the minimum forest road stretch between FR–3 and FR–7 is 110 miles.6. The length of the road directly connecting FR–3 and FR–6 is greater than 110 miles.7. The minimum forest road stretch between FR–1 and FR–4 is 110 miles, while the highest forest road stretch between FR–2 and FR–3 is 240 miles.The spys companion, Mr. Y, always travels along the shortest route when travelling from one enemy camp to another. On a particular day, both, the spy and Mr. Y, started from FR-1 and reached X, which is one of the other six enemy camps. If the length of the route that the spy took is greater than that of the route that Mr. Y took, how many of the six enemy camps were there in the route of the spy?

Directions: Read the given information carefully and answer the question that follows.A spy of XYZ kingdom regularly spies between seven enemy camps that are located inside a forest, and are connected to each other by forest roads, FR–1, FR–2, FR–3, FR–4, FR–5, FR–6, and FR–7. The spy has made a map so that he can travel with ease between camps and get the useful information required. However, while travelling between any two enemy camps, the spy always chooses the route which passes through the minimum possible number of enemy camps. If two or more routes pass through the minimum number of enemy camps, he chooses the route for which the distance is also the least. The length of the forest road, directly connecting any two enemy camps, is a multiple of 10. For any pair of enemy camps, the length of a route connecting the two enemy camps and passing through the minimum possible number of enemy camps, is called a forest road stretch between the two enemy camps. The least among all the forest road stretches between two enemy camps is called the minimum forest road stretch between the two enemy camps.The following information is known about the distances between the enemy camps:1. The minimum forest road stretch between FR–4 and FR–6 is 90 miles, while the minimum forest road stretch between FR–2 and FR–6 is 30 miles.2. The highest forest road stretch between FR–1 and FR–7 is 360 miles.3. The minimum forest road stretch between FR–4 and FR–7 is 30 miles.4. The sum of the lengths of the road directly connecting FR–5 to FR–6 and that directly connecting FR–5 and FR–7 is 100 miles.5. The minimum forest road stretch between FR–7 and FR–2 is 70 miles, while the minimum forest road stretch between FR–3 and FR–7 is 110 miles.6. The length of the road directly connecting FR–3 and FR–6 is greater than 110 miles.7. The minimum forest road stretch between FR–1 and FR–4 is 110 miles, while the highest forest road stretch between FR–2 and FR–3 is 240 miles.If the spy has to travel from FR-1 to FR-7, the distance (in miles) that the spy would have to cover is

Top Courses for CATView all

Top Courses for CAT

In a 20 km long tunnel connecting two cities A and B, there are three gutters. The distance between gutters 1 and 2 is half the distance between gutters 2 and 3. The distance from city A to its nearest gutter - gutter 1 - is equal to the distance of city B from gutter 3. On a particular day, the hospital in city A receives information that an accident has occurred at the third gutter. The victim can be saved only if an operation is started within 40 minutes. An ambulance starts from city A at 30 km/hr and crosses the first gutter after 5 minutes. If the driver doubles the speed after that, then what is the maximum amount of time the doctor will get to attend the patient at the hospital before starting the operation. Assume 1 minute elapses in taking the patient into and out of the ambulance.a)4 minutesb)2.5 minutesc)1.5 minutesd)The patient died before reaching the hospital.Correct answer is option 'C'. Can you explain this answer?
Question Description
In a 20 km long tunnel connecting two cities A and B, there are three gutters. The distance between gutters 1 and 2 is half the distance between gutters 2 and 3. The distance from city A to its nearest gutter - gutter 1 - is equal to the distance of city B from gutter 3. On a particular day, the hospital in city A receives information that an accident has occurred at the third gutter. The victim can be saved only if an operation is started within 40 minutes. An ambulance starts from city A at 30 km/hr and crosses the first gutter after 5 minutes. If the driver doubles the speed after that, then what is the maximum amount of time the doctor will get to attend the patient at the hospital before starting the operation. Assume 1 minute elapses in taking the patient into and out of the ambulance.a)4 minutesb)2.5 minutesc)1.5 minutesd)The patient died before reaching the hospital.Correct answer is option 'C'. Can you explain this answer? for CAT 2024 is part of CAT preparation. The Question and answers have been prepared according to the CAT exam syllabus. Information about In a 20 km long tunnel connecting two cities A and B, there are three gutters. The distance between gutters 1 and 2 is half the distance between gutters 2 and 3. The distance from city A to its nearest gutter - gutter 1 - is equal to the distance of city B from gutter 3. On a particular day, the hospital in city A receives information that an accident has occurred at the third gutter. The victim can be saved only if an operation is started within 40 minutes. An ambulance starts from city A at 30 km/hr and crosses the first gutter after 5 minutes. If the driver doubles the speed after that, then what is the maximum amount of time the doctor will get to attend the patient at the hospital before starting the operation. Assume 1 minute elapses in taking the patient into and out of the ambulance.a)4 minutesb)2.5 minutesc)1.5 minutesd)The patient died before reaching the hospital.Correct answer is option 'C'. Can you explain this answer? covers all topics & solutions for CAT 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for In a 20 km long tunnel connecting two cities A and B, there are three gutters. The distance between gutters 1 and 2 is half the distance between gutters 2 and 3. The distance from city A to its nearest gutter - gutter 1 - is equal to the distance of city B from gutter 3. On a particular day, the hospital in city A receives information that an accident has occurred at the third gutter. The victim can be saved only if an operation is started within 40 minutes. An ambulance starts from city A at 30 km/hr and crosses the first gutter after 5 minutes. If the driver doubles the speed after that, then what is the maximum amount of time the doctor will get to attend the patient at the hospital before starting the operation. Assume 1 minute elapses in taking the patient into and out of the ambulance.a)4 minutesb)2.5 minutesc)1.5 minutesd)The patient died before reaching the hospital.Correct answer is option 'C'. Can you explain this answer?.
Solutions for In a 20 km long tunnel connecting two cities A and B, there are three gutters. The distance between gutters 1 and 2 is half the distance between gutters 2 and 3. The distance from city A to its nearest gutter - gutter 1 - is equal to the distance of city B from gutter 3. On a particular day, the hospital in city A receives information that an accident has occurred at the third gutter. The victim can be saved only if an operation is started within 40 minutes. An ambulance starts from city A at 30 km/hr and crosses the first gutter after 5 minutes. If the driver doubles the speed after that, then what is the maximum amount of time the doctor will get to attend the patient at the hospital before starting the operation. Assume 1 minute elapses in taking the patient into and out of the ambulance.a)4 minutesb)2.5 minutesc)1.5 minutesd)The patient died before reaching the hospital.Correct answer is option 'C'. Can you explain this answer? in English & in Hindi are available as part of our courses for CAT. Download more important topics, notes, lectures and mock test series for CAT Exam by signing up for free.
Here you can find the meaning of In a 20 km long tunnel connecting two cities A and B, there are three gutters. The distance between gutters 1 and 2 is half the distance between gutters 2 and 3. The distance from city A to its nearest gutter - gutter 1 - is equal to the distance of city B from gutter 3. On a particular day, the hospital in city A receives information that an accident has occurred at the third gutter. The victim can be saved only if an operation is started within 40 minutes. An ambulance starts from city A at 30 km/hr and crosses the first gutter after 5 minutes. If the driver doubles the speed after that, then what is the maximum amount of time the doctor will get to attend the patient at the hospital before starting the operation. Assume 1 minute elapses in taking the patient into and out of the ambulance.a)4 minutesb)2.5 minutesc)1.5 minutesd)The patient died before reaching the hospital.Correct answer is option 'C'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of In a 20 km long tunnel connecting two cities A and B, there are three gutters. The distance between gutters 1 and 2 is half the distance between gutters 2 and 3. The distance from city A to its nearest gutter - gutter 1 - is equal to the distance of city B from gutter 3. On a particular day, the hospital in city A receives information that an accident has occurred at the third gutter. The victim can be saved only if an operation is started within 40 minutes. An ambulance starts from city A at 30 km/hr and crosses the first gutter after 5 minutes. If the driver doubles the speed after that, then what is the maximum amount of time the doctor will get to attend the patient at the hospital before starting the operation. Assume 1 minute elapses in taking the patient into and out of the ambulance.a)4 minutesb)2.5 minutesc)1.5 minutesd)The patient died before reaching the hospital.Correct answer is option 'C'. Can you explain this answer?, a detailed solution for In a 20 km long tunnel connecting two cities A and B, there are three gutters. The distance between gutters 1 and 2 is half the distance between gutters 2 and 3. The distance from city A to its nearest gutter - gutter 1 - is equal to the distance of city B from gutter 3. On a particular day, the hospital in city A receives information that an accident has occurred at the third gutter. The victim can be saved only if an operation is started within 40 minutes. An ambulance starts from city A at 30 km/hr and crosses the first gutter after 5 minutes. If the driver doubles the speed after that, then what is the maximum amount of time the doctor will get to attend the patient at the hospital before starting the operation. Assume 1 minute elapses in taking the patient into and out of the ambulance.a)4 minutesb)2.5 minutesc)1.5 minutesd)The patient died before reaching the hospital.Correct answer is option 'C'. Can you explain this answer? has been provided alongside types of In a 20 km long tunnel connecting two cities A and B, there are three gutters. The distance between gutters 1 and 2 is half the distance between gutters 2 and 3. The distance from city A to its nearest gutter - gutter 1 - is equal to the distance of city B from gutter 3. On a particular day, the hospital in city A receives information that an accident has occurred at the third gutter. The victim can be saved only if an operation is started within 40 minutes. An ambulance starts from city A at 30 km/hr and crosses the first gutter after 5 minutes. If the driver doubles the speed after that, then what is the maximum amount of time the doctor will get to attend the patient at the hospital before starting the operation. Assume 1 minute elapses in taking the patient into and out of the ambulance.a)4 minutesb)2.5 minutesc)1.5 minutesd)The patient died before reaching the hospital.Correct answer is option 'C'. Can you explain this answer? theory, EduRev gives you an ample number of questions to practice In a 20 km long tunnel connecting two cities A and B, there are three gutters. The distance between gutters 1 and 2 is half the distance between gutters 2 and 3. The distance from city A to its nearest gutter - gutter 1 - is equal to the distance of city B from gutter 3. On a particular day, the hospital in city A receives information that an accident has occurred at the third gutter. The victim can be saved only if an operation is started within 40 minutes. An ambulance starts from city A at 30 km/hr and crosses the first gutter after 5 minutes. If the driver doubles the speed after that, then what is the maximum amount of time the doctor will get to attend the patient at the hospital before starting the operation. Assume 1 minute elapses in taking the patient into and out of the ambulance.a)4 minutesb)2.5 minutesc)1.5 minutesd)The patient died before reaching the hospital.Correct answer is option 'C'. Can you explain this answer? tests, examples and also practice CAT tests.
Explore Courses for CAT exam

Top Courses for CAT

Explore Courses

Suggested Free Tests

Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
10M+ students study on EduRev
Get App
© EduRev
Education Revolution
Signup to see your scores go up within 7 days!
Access 1000+ FREE Docs, Videos and Tests
Takes less than 10 seconds to signup