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If x= 4/ (under-root 5 1)(⁴underroot5 1) (⁸underrot5 1) (¹⁶under root 5 1) then value of (1 x) greater than?
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If x= 4/ (under-root 5 1)(⁴underroot5 1) (⁸underrot5 1) (¹⁶under root ...
Solution:

Given: x = 4/√5(1)(⁴√5(1))(⁸√5(1))(¹⁶√5(1))

To find: Value of (1 + x)

Step 1: Simplify x

x = 4/√5(1)(⁴√5(1))(⁸√5(1))(¹⁶√5(1))

= 4/√5(1)(⁴√5(1))(⁸√5(1))(²√5(4))

= 4/√5(1)(⁴√5(1))(⁶√5(2))(²√5(4))

= 4/√5(1)(⁴√5(1))(⁶√5(2))(²√5(2)²)

= 4/√5(1)(⁴√5(1))(⁶√5(2))(²√5(2))²

= 4/√5(1)(⁴√5(1))(⁶√5(2))(√5(2))²

= 4/(√5)²(⁴√5(1))(⁶√5(2))(√5(2))²

= 4/5(⁴√5(1))(⁶√5(2))(2)

= 4/20(⁴√5(1))(⁶√5(2))

= 1/(5(⁶√5(2))(⁴√5(1)))

Step 2: Find the value of (1 + x)

(1 + x) = 1 + 1/(5(⁶√5(2))(⁴√5(1)))

Step 3: Simplify (1 + x)

Multiplying numerator and denominator by (⁶√5(2))(⁴√5(1)), we get

(1 + x) = (⁶√5(2))(⁴√5(1))/(5(⁶√5(2))(⁴√5(1))) + 1

= (⁶√5(2))(⁴√5(1))/(5(⁶√5(2))(⁴√5(1))) + 5/5

= (⁶√5(2))(⁴√5(1)) + 5 / (5(⁶√5(2))(⁴√5(1)))

= (⁶√5(2))(⁴√5(1)) / (⁶√5(2))(⁴√5(1))

= 1

Therefore, (1 + x) = 1

Answer: The value of (1 + x) is 1.
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If x= 4/ (under-root 5 1)(⁴underroot5 1) (⁸underrot5 1) (¹⁶under root 5 1) then value of (1 x) greater than?
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If x= 4/ (under-root 5 1)(⁴underroot5 1) (⁸underrot5 1) (¹⁶under root 5 1) then value of (1 x) greater than? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about If x= 4/ (under-root 5 1)(⁴underroot5 1) (⁸underrot5 1) (¹⁶under root 5 1) then value of (1 x) greater than? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for If x= 4/ (under-root 5 1)(⁴underroot5 1) (⁸underrot5 1) (¹⁶under root 5 1) then value of (1 x) greater than?.
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