If 2 is a root of the quadratic equation 3x² + px - 8 = 0 and the quad...
2 is a root if the equation 3x^2 +px-8=0.`. 3(2)^2+p(2)-8=0 =》12+2p-8=0=》4+2p=0=》p=-2Now,4x^2-2px+k=0 =》4x^2+4x+k=0 It has equal roots .`.D=0 =》(4)^2-4×4×k=0=》16-16k=0=》16(1-k)=0=》1-k=0=》k=1 Hence, k= 1
If 2 is a root of the quadratic equation 3x² + px - 8 = 0 and the quad...
Solution:
We are given that 2 is a root of the quadratic equation 3x² px - 8 = 0.
Let us use the factor theorem to factorize this quadratic equation.
Factor Theorem: If c is a root of the polynomial f(x), then (x-c) is a factor of f(x).
Since 2 is a root of 3x² px - 8 = 0, we can say that (x-2) is a factor of 3x² px - 8 = 0.
We can use this information to find the value of p.
Using Factor Theorem:
Let f(x) = 3x² px - 8
Since (x-2) is a factor of f(x), we can say that f(2) = 0.
f(2) = 3(2)² p(2) - 8
0 = 12 - 2p - 8
0 = 4 - 2p
2 = p
We have found the value of p.
Now, let us use this value of p to find the value of k in the quadratic equation 4x² - 2px k = 0.
Using Discriminant:
The quadratic equation 4x² - 2px k = 0 has equal roots.
This means that the discriminant of the quadratic equation is zero.
The discriminant of a quadratic equation ax² + bx + c = 0 is given by b² - 4ac.
If the discriminant is zero, then b² - 4ac = 0.
In our case, the quadratic equation is 4x² - 2px k = 0.
So, a = 4, b = -2p and c = k.
Substituting these values in the discriminant, we get:
(-2p)² - 4(4)(k) = 0
4p² - 16k = 0
4p² = 16k
k = (4p²)/16
k = p²/4
k = 1
Therefore, the value of k is 1.