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The angle of minimum deviation for a prism of refractive index 3/2 is equal to the angle of prism. The angle of prism is
  • a)
    42°
  • b)
    82°
  • c)
    41°
  • d)
    31°
Correct answer is option 'B'. Can you explain this answer?
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The angle of minimum deviation for a prism of refractive index 3/2 is ...
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The angle of minimum deviation for a prism of refractive index 3/2 is ...
Explanation:

Angle of minimum deviation:
- The angle of minimum deviation for a prism is the angle at which the deviation of light passing through the prism is minimized.
- This angle can be calculated using the formula: A = (A1 + A2) / 2 - δm

Angle of prism:
- The angle of the prism is the angle between the two non-parallel surfaces of the prism.
- This angle is denoted by the symbol 'A'.

Given conditions:
- It is given that the angle of minimum deviation for the prism is equal to the angle of the prism.
- Therefore, A = δm

Calculating the angle of prism:
- From the formula for the angle of minimum deviation, we have A = (A1 + A2) / 2 - δm
- Since A = δm, we can substitute A for δm in the formula: A = (A1 + A2) / 2 - A
- Simplifying the equation, we get 2A = (A1 + A2)
- Since A1 + A2 is the angle of the prism, we can conclude that the angle of the prism is twice the angle of minimum deviation.

Conclusion:
- Therefore, if the angle of minimum deviation for a prism of refractive index 3/2 is equal to the angle of the prism, then the angle of the prism is 2 times the angle of minimum deviation.
- The correct answer is option 'B', which is 82°.
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The angle of minimum deviation for a prism of refractive index 3/2 is equal to the angle of prism. The angle of prism isa)42°b)82°c)41°d)31°Correct answer is option 'B'. Can you explain this answer?
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