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The energy of activation of a reaction is 150 kJ/mol. Presence of a catalyst lowers the activation energy by 60%. If r1 is the rate of the reaction without the catalyst and r2 is the rate of the reaction with the catalyst at 25oC, then the value of  if all other conditions remain the same, will be
  • a)
    2.031
  • b)
    1.0244
  • c)
    r1 = r2
  • d)
    6.012
Correct answer is option 'B'. Can you explain this answer?
Most Upvoted Answer
The energy of activation of a reaction is 150 kJ/mol. Presence of a ca...
We know, k = Ae-Ea/RT
Hence, k1 = Ae-150/RT …(1)
k2 = Ae-90/RT …(2)
From (1) and (2), we get
Taking log on both sides, we get
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The energy of activation of a reaction is 150 kJ/mol. Presence of a catalyst lowers the activation energy by 60%. If r1 is the rate of the reaction without the catalyst and r2 is the rate of the reaction with the catalyst at 25oC, then the value ofif all other conditions remain the same, will bea)2.031b)1.0244c)r1 = r2d)6.012Correct answer is option 'B'. Can you explain this answer? for JEE 2025 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about The energy of activation of a reaction is 150 kJ/mol. Presence of a catalyst lowers the activation energy by 60%. If r1 is the rate of the reaction without the catalyst and r2 is the rate of the reaction with the catalyst at 25oC, then the value ofif all other conditions remain the same, will bea)2.031b)1.0244c)r1 = r2d)6.012Correct answer is option 'B'. Can you explain this answer? covers all topics & solutions for JEE 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The energy of activation of a reaction is 150 kJ/mol. Presence of a catalyst lowers the activation energy by 60%. If r1 is the rate of the reaction without the catalyst and r2 is the rate of the reaction with the catalyst at 25oC, then the value ofif all other conditions remain the same, will bea)2.031b)1.0244c)r1 = r2d)6.012Correct answer is option 'B'. Can you explain this answer?.
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