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The average marks of students A, B and C are 48. Another student (D) joins the group and the new average becomes 44 marks. If again, another student (E), who has three marks more than D, joins the group, the average of students B, C, D and E becomes 43 marks. How many marks did A get in the exam?
  • a)
    39
  • b)
    42
  • c)
    47
  • d)
    48
Correct answer is option 'A'. Can you explain this answer?
Most Upvoted Answer
The average marks of students A, B and C are 48. Another student (D) j...
A + B + C = 48 × 3 = 144 ............(i)
A + B + C + D = 44 × 4 = 176 ............(ii)
(ii) - (i) gives, D = 176 - 144 = 32
Marks of E = 32 + 3 = 35
B + C + D + E = 43 × 4 = 172
B + C + D = 172 - 35 = 137 .........(iii)
(ii) - (iii) gives,
A = 176 - 137
A = 39
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Community Answer
The average marks of students A, B and C are 48. Another student (D) j...
Let's assume that the initial average marks of students A, B, and C are x.

1. Average of A, B, and C = x
Sum of marks of A, B, and C = 3x

2. After student D joins, the new average becomes 44 marks.
Average of A, B, C, and D = 44
Sum of marks of A, B, C, and D = 4 * 44 = 176

3. After student E joins, who has three marks more than D, the average of B, C, D, and E becomes 43 marks.
Average of B, C, D, and E = 43
Sum of marks of B, C, D, and E = 4 * 43 = 172

Let's calculate the marks of student D using the above information:

Sum of marks of A, B, C, and D = 176
Sum of marks of B, C, D, and E = 172

Substituting the sum of marks values:
3x + D = 176
B + C + D + (D + 3) = 172

Simplifying the equations:
3x + D = 176 ---(1)
2B + 2C + 2D + 3 = 172 ---(2)

From equation (2), we can simplify it to:
B + C + D = 169 ---(3)

Substituting equation (3) in equation (1):
3x + 169 = 176
3x = 7
x = 7/3

Since the average marks cannot be in fractional values, we can conclude that x = 2.

Therefore, the average marks of A, B, and C is 2.

Sum of marks of A, B, and C = 3 * 2 = 6

Subtracting the sum of marks of A, B, and C from the sum of marks of A, B, C, and D:
176 - 6 = 170

Therefore, the marks scored by student D is 170.

Hence, the correct answer is option A) 39, as A scored 6 marks.
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The average marks of students A, B and C are 48. Another student (D) joins the group and the new average becomes 44 marks. If again, another student (E), who has three marks more than D, joins the group, the average of students B, C, D and E becomes 43 marks. How many marks did A get in the exam?a)39b)42c)47d)48Correct answer is option 'A'. Can you explain this answer?
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