The average marks of 3 students A,B and D is 48 marks. Another student...
Problem:
The average marks of 3 students A,B and D is 48 marks. Another student D joins the group and the new average becomes 44 marks. If another student E, who has 3 marks more than D, joins the group, the average of the 4 students B,C,D and E bacomes 43 marks. Find how many marks A got in the exam.?
Solution:
Let's solve the problem by following the below steps:
Step 1: Find the total marks of A, B and D
As per the given problem, the average marks of A, B, and D is 48. Let's assume the total marks of A, B, and D to be 'x'
Therefore, (x/3) = 48 => x = 144
So, the total marks of A, B, and D is 144.
Step 2: Find the marks of D
When D joins the group, the new average becomes 44. Therefore, the total marks of A, B, D, and D is:
(Total marks of A, B, and D) + (Marks of D) = 4 x 44
144 + (Marks of D) = 176
Marks of D = 32
Step 3: Find the marks of E
As per the given problem, E has 3 marks more than D. Therefore, the marks of E is:
Marks of E = Marks of D + 3 = 32 + 3 = 35
Step 4: Find the total marks of B, C, D, and E
As per the given problem, the average of B, C, D, and E is 43. Let's assume the total marks of B, C, D, and E to be 'y'.
Therefore, (y/4) = 43 => y = 172
So, the total marks of B, C, D, and E is 172.
Step 5: Find the marks of A
Now, we can find the marks of A by subtracting the total marks of B, C, D, and E from the total marks of A, B, and D.
Marks of A = (Total marks of A, B, and D) - (Total marks of B, C, D, and E)
Marks of A = 144 - 172 = -28
Step 6: Conclusion
As we can see, the marks of A is -28 which is not possible. Therefore, there must be some mistake in the problem statement or the data provided.