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A bird is sitting in a large closed cage which is placed on a spring balance. It records a weight of 25 N. The bird (mass m = 0.5 kg) flies upward in the cage with an acceleration of 2 ms−2. The spring balance will now record a weight of
- a)24 N
- b)26 N
- c)25 N
- d)27 N
Correct answer is option 'B'. Can you explain this answer?
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Most Upvoted Answer
A bird is sitting in a large closed cage which is placed on a spring b...
When the bird is at rest inside the cage, the spring balance records its weight, which is equal to the gravitational force acting on it, i.e., 25 N.
When the bird flies upward in the cage with an acceleration of 2 m/s^2, the net force acting on the bird is given by:
F = m*a
where F is the net force, m is the mass of the bird, and a is the acceleration.
F = 0.5 kg * 2 m/s^2 = 1 N
This means that the bird is exerting an additional force of 1 N upwards while flying.
Therefore, the spring balance will now record a weight of:
W = 25 N + 1 N = 26 N
So the spring balance will now record a weight of 26 N.
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Community Answer
A bird is sitting in a large closed cage which is placed on a spring b...
-2.
The weight recorded on the spring balance will momentarily decrease. This is because the upward force exerted by the bird (equal to its weight minus the force needed to accelerate it upward) is less than its weight when it was at rest.
Using Newton's second law, we can calculate the force exerted by the bird when it flies upward:
F = ma = 0.5 kg x 2 m/s^2 = 1 N
Therefore, the weight recorded on the spring balance will decrease by 1 N, from 25 N to 24 N, while the bird is flying upward in the cage with an acceleration of 2 m/s^2.
The weight recorded on the spring balance will momentarily decrease. This is because the upward force exerted by the bird (equal to its weight minus the force needed to accelerate it upward) is less than its weight when it was at rest.
Using Newton's second law, we can calculate the force exerted by the bird when it flies upward:
F = ma = 0.5 kg x 2 m/s^2 = 1 N
Therefore, the weight recorded on the spring balance will decrease by 1 N, from 25 N to 24 N, while the bird is flying upward in the cage with an acceleration of 2 m/s^2.
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A bird is sitting in a large closed cage which is placed on a spring balance. It records a weight of 25 N. The bird (mass m = 0.5 kg) flies upward in the cage with an acceleration of 2 ms−2. The spring balance will now record a weight ofa)24 Nb)26 Nc)25 Nd)27 NCorrect answer is option 'B'. Can you explain this answer?
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