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 If one rot of 5x2+13x+p=0 be reciprocal of the other then the value of p is
  • a)
     -5
  • b)
    5
  • c)
    1/5
  • d)
     -1/5
Correct answer is option 'B'. Can you explain this answer?
Most Upvoted Answer
If one rot of 5x2+13x+p=0 be reciprocal of the other then the value of...
Given equation: 5x^2 + 13x + p = 0

To find: The value of p when one root is the reciprocal of the other

Solution:

Let the roots of the equation be α and β. Then, we know that:

αβ = p/5 ----(1)

α + β = -13/5 ----(2)

Also, given that one root is the reciprocal of the other. Let's assume that α is the reciprocal of β. Then,

αβ = 1 ----(3)

From equations (1) and (3), we get:

p/5 = 1

p = 5

Therefore, the value of p is 5, which is option (B).

Note: We could also assume that β is the reciprocal of α and follow the same steps to arrive at the same answer.
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If one rot of 5x2+13x+p=0 be reciprocal of the other then the value of p isa)-5b)5c)1/5d)-1/5Correct answer is option 'B'. Can you explain this answer?
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