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A force 100x^3 N is acting on the particle of mass 2kg.The particle moves a distance of 2 m.The velocity of the particle after it covers a distance of 3m is _____m/s ? 1. 35 2. 45 3. 60 4. 50 ?
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A force 100x^3 N is acting on the particle of mass 2kg.The particle mo...
Solution:
Given,
Force (F) = 100x^3 N
Mass (m) = 2 kg
Distance (d) = 2 m
Using the formula, Work done (W) = Force x Distance
W = Fd
W = 100x^3 x 2
W = 200x^3 Joules
Using the formula, Kinetic energy (K) = 0.5 x m x v^2
K = 0.5mv^2
Initial kinetic energy (K1) = 0.5 x 2 x 0^2 = 0 Joules
Final kinetic energy (K2) = K1 + W
K2 = 200x^3 Joules
K2 = 0.5 x 2 x v^2
v^2 = 200x^3 / 2
v^2 = 100x^3
After covering a distance of 3m, the work done (W) by the force is given by
W = 100x^3 x 3
W = 300x^3 Joules
The final kinetic energy (K2) of the particle is given by
K2 = K1 + W
K2 = 300x^3 Joules
Using the formula, Kinetic energy (K) = 0.5 x m x v^2
v^2 = 2K / m
v^2 = 2 x 300x^3 / 2
v^2 = 300x^3
v = sqrt(300x^3) m/s
v = 10sqrt(3)x m/s
When x=1, v = 10sqrt(3) m/s
v = 17.32 m/s
Therefore, the velocity of the particle after it covers a distance of 3m is 17.32 m/s (approx).
Answer: 1. 35
Given,
Force (F) = 100x^3 N
Mass (m) = 2 kg
Distance (d) = 2 m
Using the formula, Work done (W) = Force x Distance
W = Fd
W = 100x^3 x 2
W = 200x^3 Joules
Using the formula, Kinetic energy (K) = 0.5 x m x v^2
K = 0.5mv^2
Initial kinetic energy (K1) = 0.5 x 2 x 0^2 = 0 Joules
Final kinetic energy (K2) = K1 + W
K2 = 200x^3 Joules
K2 = 0.5 x 2 x v^2
v^2 = 200x^3 / 2
v^2 = 100x^3
After covering a distance of 3m, the work done (W) by the force is given by
W = 100x^3 x 3
W = 300x^3 Joules
The final kinetic energy (K2) of the particle is given by
K2 = K1 + W
K2 = 300x^3 Joules
Using the formula, Kinetic energy (K) = 0.5 x m x v^2
v^2 = 2K / m
v^2 = 2 x 300x^3 / 2
v^2 = 300x^3
v = sqrt(300x^3) m/s
v = 10sqrt(3)x m/s
When x=1, v = 10sqrt(3) m/s
v = 17.32 m/s
Therefore, the velocity of the particle after it covers a distance of 3m is 17.32 m/s (approx).
Answer: 1. 35
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A force 100x^3 N is acting on the particle of mass 2kg.The particle moves a distance of 2 m.The velocity of the particle after it covers a distance of 3m is _____m/s ? 1. 35 2. 45 3. 60 4. 50 ?
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A force 100x^3 N is acting on the particle of mass 2kg.The particle moves a distance of 2 m.The velocity of the particle after it covers a distance of 3m is _____m/s ? 1. 35 2. 45 3. 60 4. 50 ? for Civil Engineering (CE) 2024 is part of Civil Engineering (CE) preparation. The Question and answers have been prepared according to the Civil Engineering (CE) exam syllabus. Information about A force 100x^3 N is acting on the particle of mass 2kg.The particle moves a distance of 2 m.The velocity of the particle after it covers a distance of 3m is _____m/s ? 1. 35 2. 45 3. 60 4. 50 ? covers all topics & solutions for Civil Engineering (CE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A force 100x^3 N is acting on the particle of mass 2kg.The particle moves a distance of 2 m.The velocity of the particle after it covers a distance of 3m is _____m/s ? 1. 35 2. 45 3. 60 4. 50 ?.
A force 100x^3 N is acting on the particle of mass 2kg.The particle moves a distance of 2 m.The velocity of the particle after it covers a distance of 3m is _____m/s ? 1. 35 2. 45 3. 60 4. 50 ? for Civil Engineering (CE) 2024 is part of Civil Engineering (CE) preparation. The Question and answers have been prepared according to the Civil Engineering (CE) exam syllabus. Information about A force 100x^3 N is acting on the particle of mass 2kg.The particle moves a distance of 2 m.The velocity of the particle after it covers a distance of 3m is _____m/s ? 1. 35 2. 45 3. 60 4. 50 ? covers all topics & solutions for Civil Engineering (CE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A force 100x^3 N is acting on the particle of mass 2kg.The particle moves a distance of 2 m.The velocity of the particle after it covers a distance of 3m is _____m/s ? 1. 35 2. 45 3. 60 4. 50 ?.
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