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An object is moving along a straight path with a constant acceleration of 4m/s². Calculate the change in velocity of the object in 5s.?
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An object is moving along a straight path with a constant acceleration...
Calculating Change in Velocity of an Object with Constant Acceleration
When an object moves along a straight path with a constant acceleration, we can calculate the change in velocity of the object in a given time period using the following formula:
Δv = a × t
where Δv is the change in velocity, a is the constant acceleration, and t is the time period.
Given Information
In this case, we are given that the object has a constant acceleration of 4m/s² and we need to calculate the change in velocity of the object in 5 seconds.
Calculating the Change in Velocity
Using the formula above, we can calculate the change in velocity of the object as follows:
Δv = 4m/s² × 5s
Δv = 20m/s
Therefore, the change in velocity of the object in 5 seconds is 20m/s.
Explanation
When an object moves with a constant acceleration, its velocity changes at a constant rate. This means that we can use the formula Δv = a × t to calculate the change in velocity over a given time period. In this case, we were given the constant acceleration of the object (4m/s²) and the time period (5 seconds). By plugging these values into the formula, we were able to calculate the change in velocity of the object over the given time period.
When an object moves along a straight path with a constant acceleration, we can calculate the change in velocity of the object in a given time period using the following formula:
Δv = a × t
where Δv is the change in velocity, a is the constant acceleration, and t is the time period.
Given Information
In this case, we are given that the object has a constant acceleration of 4m/s² and we need to calculate the change in velocity of the object in 5 seconds.
Calculating the Change in Velocity
Using the formula above, we can calculate the change in velocity of the object as follows:
Δv = 4m/s² × 5s
Δv = 20m/s
Therefore, the change in velocity of the object in 5 seconds is 20m/s.
Explanation
When an object moves with a constant acceleration, its velocity changes at a constant rate. This means that we can use the formula Δv = a × t to calculate the change in velocity over a given time period. In this case, we were given the constant acceleration of the object (4m/s²) and the time period (5 seconds). By plugging these values into the formula, we were able to calculate the change in velocity of the object over the given time period.
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An object is moving along a straight path with a constant acceleration of 4m/s². Calculate the change in velocity of the object in 5s.?
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An object is moving along a straight path with a constant acceleration of 4m/s². Calculate the change in velocity of the object in 5s.? for Class 9 2024 is part of Class 9 preparation. The Question and answers have been prepared according to the Class 9 exam syllabus. Information about An object is moving along a straight path with a constant acceleration of 4m/s². Calculate the change in velocity of the object in 5s.? covers all topics & solutions for Class 9 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for An object is moving along a straight path with a constant acceleration of 4m/s². Calculate the change in velocity of the object in 5s.?.
An object is moving along a straight path with a constant acceleration of 4m/s². Calculate the change in velocity of the object in 5s.? for Class 9 2024 is part of Class 9 preparation. The Question and answers have been prepared according to the Class 9 exam syllabus. Information about An object is moving along a straight path with a constant acceleration of 4m/s². Calculate the change in velocity of the object in 5s.? covers all topics & solutions for Class 9 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for An object is moving along a straight path with a constant acceleration of 4m/s². Calculate the change in velocity of the object in 5s.?.
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