A, B and C together can finish a piece of work in 12 days. A and C tog...
Since A and C together work twice as much as B
A + C = 2B ... (1)
And A and B together work thrice as much as C
A + B = 3C ... (2)
Equation (1) - equation (2) gives
C - B = 2B - 3C
Or 3B = 4C
Or B = (4/3)C
Substituting this relation in equation (1), we get
A = (5/3)C
A + B + C = (5/3)C + (4/3)C + C = 4C
This means that 4C can complete the work in 12 days or C can complete in 12 x 4 = 48 days.
A, B and C together can finish a piece of work in 12 days. A and C tog...
Let's assume that the work done by A, B, and C in one day is represented by the variables a, b, and c respectively.
According to the given information:
- A, B, and C together can finish a piece of work in 12 days.
This implies that their combined daily work is equal to 1/12th of the total work. Therefore, we have the equation: a + b + c = 1/12.
- A and C together work twice as much as B.
This means that their combined daily work is equal to twice the work done by B. So, we have the equation: a + c = 2b.
- A and B together work thrice as much as C.
This implies that their combined daily work is equal to three times the work done by C. So, we have the equation: a + b = 3c.
We now have a system of three equations with three variables. We can solve this system to find the values of a, b, and c.
Solving the system of equations:
From the equation a + c = 2b, we can rewrite it as a = 2b - c.
Substituting this value of a in the equation a + b = 3c, we get:
2b - c + b = 3c
3b = 4c
b = (4/3)c
Substituting the value of b in the equation a + b + c = 1/12, we get:
a + (4/3)c + c = 1/12
a + (7/3)c = 1/12
Since a + b + c = 1/12, we can substitute the value of a + c = 2b in this equation:
2b + b = 1/12
3b = 1/12
b = 1/36
Substituting the value of b = (4/3)c in this equation, we get:
(4/3)c = 1/36
c = 1/36 * 3/4
c = 1/48
Therefore, C can finish the job alone in 48 days.
Hence, option B is the correct answer.