Manoj takes twice as much time as Anjay and thrice as much as Vijay to...
Let Anjay take 3t days, Vijay take 2t days and Manoj take 6t days in order to complete the work. Then we get: 1/3t +
1/2t + 1/6t = 1 → t = 1. Thus, Manoj would take 6t = 6 days to complete the work.
Manoj takes twice as much time as Anjay and thrice as much as Vijay to...
Given Information:
- Manoj takes twice as much time as Anjay and thrice as much as Vijay to finish the work.
- Together they finish the work in 1 day.
Let's Find the Individual Time taken by Anjay, Vijay, and Manoj:
- Let Anjay take x days to finish the work.
- Manoj takes twice as much time as Anjay, so Manoj takes 2x days to finish the work.
- Vijay takes thrice as much time as Vijay, so Vijay takes 3x days to finish the work.
Calculating Total Work Done in 1 Day:
- In 1 day, Anjay completes 1/x of the work.
- In 1 day, Manoj completes 1/2x of the work.
- In 1 day, Vijay completes 1/3x of the work.
- Together, they complete the work in 1 day, so:
1/x + 1/2x + 1/3x = 1
(6 + 3 + 2)/6x = 1
11/6x = 1
x = 11/6
Calculating the Time taken by Manoj to Finish the Work:
- Manoj takes 2x days to finish the work.
- Substituting x = 11/6 into the equation:
Manoj takes 2*(11/6) = 22/6 = 11/3 days to finish the work.
Therefore, the Time taken by Manoj to finish the work is 11/3 days, which is approximately 3.67 days.
So, the correct answer is option A) 6 days.