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The minimum number of J K flip-flops required to construct a synchronous counter with the sequence like (0, 0, 1, 1, 2, 2, 3, 3, 0, 0, ...) is:-
- a)0
- b)1
- c)2
- d)3
Correct answer is option 'D'. Can you explain this answer?
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Most Upvoted Answer
The minimum number of J K flip-flops required to construct a synchrono...
The given sequence (0, 0, 1, 1, 2, 2, 3, 3, 0, 0, ...) represents a counter that counts from 0 to 3 and then repeats. To construct such a counter using J-K flip-flops, we need to determine the minimum number of flip-flops required.
A J-K flip-flop is a type of flip-flop that has two inputs, J (set) and K (reset), and two outputs, Q (output) and Q' (complement output). The flip-flop changes its output state based on the inputs and the current state.
To implement a counter, we need to consider the number of states in the counter and the number of flip-flops required to represent these states.
Let's analyze the given sequence:
- The counter goes from 0 to 3, which requires 4 states (0, 1, 2, 3).
- Each state is represented by a binary number: 00, 01, 10, 11.
To represent 4 states, we need at least 2 flip-flops because 2 flip-flops can represent 2^2 = 4 unique states.
Now, let's determine the number of flip-flops required to represent the given sequence.
- In the given sequence, each state appears twice before moving to the next state.
- This means that we need to store the previous state in order to determine the next state.
To store the previous state, we need an additional flip-flop. This flip-flop will store the current state, and the other two flip-flops will store the next state.
Therefore, the minimum number of J-K flip-flops required to construct a synchronous counter with the given sequence is 2 (for storing the next state) + 1 (for storing the previous state) = 3 flip-flops.
Hence, the correct answer is option D) 3.
A J-K flip-flop is a type of flip-flop that has two inputs, J (set) and K (reset), and two outputs, Q (output) and Q' (complement output). The flip-flop changes its output state based on the inputs and the current state.
To implement a counter, we need to consider the number of states in the counter and the number of flip-flops required to represent these states.
Let's analyze the given sequence:
- The counter goes from 0 to 3, which requires 4 states (0, 1, 2, 3).
- Each state is represented by a binary number: 00, 01, 10, 11.
To represent 4 states, we need at least 2 flip-flops because 2 flip-flops can represent 2^2 = 4 unique states.
Now, let's determine the number of flip-flops required to represent the given sequence.
- In the given sequence, each state appears twice before moving to the next state.
- This means that we need to store the previous state in order to determine the next state.
To store the previous state, we need an additional flip-flop. This flip-flop will store the current state, and the other two flip-flops will store the next state.
Therefore, the minimum number of J-K flip-flops required to construct a synchronous counter with the given sequence is 2 (for storing the next state) + 1 (for storing the previous state) = 3 flip-flops.
Hence, the correct answer is option D) 3.
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Community Answer
The minimum number of J K flip-flops required to construct a synchrono...
Count sequence is 00, 00, 01, 01, 10, 10, 11, 11 the repeated sequence is above present. As two bits will not be sufficient, we need at least three flip-flops. So, the answer is 3.
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The minimum number of J K flip-flops required to construct a synchronous counter with the sequence like (0, 0, 1, 1, 2, 2, 3, 3, 0, 0, ...) is:-a)0b)1c)2d)3Correct answer is option 'D'. Can you explain this answer?
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